repeating a vector with increments

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Jeong Ho
Jeong Ho le 20 Fév 2015
Réponse apportée : arich82 le 20 Fév 2015
Dear Matlab Central users, Hi, I have a row vector I and I want to create a row vector [I I+n I+2*n ... I+(N-1)*n] where N>1 and n are positive integers. For example, if I = [2 3] and N = n = 3, [2 3 5 6 6 9] Is there a trick to doing this efficiently? Thank you all!
Best, John

Réponses (2)

Star Strider
Star Strider le 20 Fév 2015
The output vector you listed does not seem to me to correspond to the rule for it you posted. Please clarify.
This otherwise seems to work:
N = 3;
I = [2 3];
Q = (cumsum(ones(N,2))-1)*N;
Ym = bsxfun(@plus, I, Q);
Yv = reshape(Ym', 1, []); % Output
produces:
Yv =
2 3 5 6 8 9

arich82
arich82 le 20 Fév 2015
Assuming you have a typo in your example and your desired output is actually
[2, 3, 5, 8, 9]
(i.e. an 8 instead of the repeated 6), then I think this should do what you want:
n = 3;
N = 3;
a = [2, 3];
b = n*[0:N-1];
c = bsxfun(@plus, a.', b);
c = c(:).'
or as a messy one-liner:
reshape(bsxfun(@plus, [2, 3].', 3*(0:3-1)), 1, []);
No gurantees that someone won't have a more clever solution, but if this doesn't give the desired result, perhaps a little more clarification would be helpful.

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