Shifting graph vertically upwards

I have a simple qn:

I want to shift a graph vertically upwards.

vert_offset = kneeV(1) - kneeangle(1);
peak_x = peak_x + horz_offset;
peak_y = peak_y + vert_offset;
kneeangle = [zeros(horz_offset,1); kneeangle];
kneeangle = kneeangle + vert_offset;

what i did was this, but my graph did not move upwards and only move sidewards. The graph only moved upwards when I plotted kneeangle+vert_offset instead of kneeangle.

Just for additional information, the kneeangle is a column array that is the y-value of my graph.

[Geoff Hayes]

Mich - what is the line of code that you are using to plot your data?

[Image Analyst]

What is kneeangle supposed to be higher than? It looks like you just pushed it to the right by prepending a bunch of zeros to the top of the array.

[Mich]

I'm comparing 2 sets of data, kneeV and kneeangle. Currently, the baseline value (initial value) for knee V is higher than kneeangle and greater in the x-direction too, so I would like to shift the graph for kneeangle to the right and of the same baseline as kneeV so that I can do a proper peak-to-peak comparison and obtain the error difference.

I've inserted an image of my graph obtained when I plot kneeangle+vert_offset

kneeangle- blue ,kneeV- black

Answer 1

[Image Analyst]

Try this, aligning the means in the pulse train region:

% Crop the array
index = find(blueSignal > 1, 1, 'first');
% Get the mean
blueMean = mean(blueSignal(index:end));
% Now the same for the other black signal
% Crop the array
index = find(blackSignal > 1, 1, 'first');
% Get the mean
blackMean = mean(blackSignal (index:end));
% Subtract the blue mean and add the black mean to the blue signal
shiftedBueSignal = blueSignal - blueMean + blackMean;
plot(blackSignal);
hold on;
plot(shiftedBueSignal);