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Effacer les filtres

Finding root of nonlinear functions

1 vue (au cours des 30 derniers jours)
University Glasgow
University Glasgow le 8 Sep 2022
Commenté : Sam Chak le 8 Sep 2022
Please, how do I find all the roots this function:
y-0.8193318913*tanh(y)+0.2931044702e-2*tanh(y)/(0.7500000000e-3*y^2-0.1622336517e-1) = 0

Réponse acceptée

Torsten
Torsten le 8 Sep 2022
f = @(y)(y-0.8193318913*tanh(y)).*(0.7500000000e-3*y.^2-0.1622336517e-1)+0.2931044702e-2*tanh(y);
fun = @(y)f(y)./(0.7500000000e-3*y.^2-0.1622336517e-1);
y = -6:0.01:6;
plot(y,f(y))
x0 = [-5 -4];
s(1) = fzero(f,x0);
x0 = [-1 1];
s(2) = fzero(f,x0);
x0 = [4 5];
s(3) = fzero(f,x0);
s
s = 1×3
-4.5365 0 4.5365
fun(s)
ans = 1×3
1.0e-14 * 0.4951 0 -0.4951
  1 commentaire
Sam Chak
Sam Chak le 8 Sep 2022
👍, Yes, follow this method to find all real roots.

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Sam Chak
Sam Chak le 8 Sep 2022
Read about fzero().
The solution may look like this:
fun = @(y) y - 0.8193318913*tanh(y) + (0.2931044702e-2)*tanh(y)./(0.7500000000e-3*y.^2 - 0.1622336517e-1);
y0 = 0; % initial guess
y = fzero(fun, y0)
y = 0

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