Heat transient equation not executing

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Reji G
Reji G le 17 Sep 2022
Commenté : Torsten le 17 Sep 2022
I want to implement this formula in matlab. But i couldn't. So it'd be great if anyone can help me. Where x&t ranges from 0.1 to 10.
  2 commentaires
Torsten
Torsten le 17 Sep 2022
Please show us your attempt.
Reji G
Reji G le 17 Sep 2022
Déplacé(e) : Star Strider le 17 Sep 2022
clc;
close all;
clear all;
T1=300;
Ti = 350;
L = 10;
alpha = 100;
syms n
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,9)
T(x,t) = T1+((4/pi)*(Ti-T1)*T);

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Réponses (1)

Torsten
Torsten le 17 Sep 2022
The terms in your series do not agree with the formula you posted.
You must decide which one is correct and which one is wrong.
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.1:L;
t = 0:0.1:1;
[X,TIME] = meshgrid(x,t);
surf(TIME,X,T(TIME,X))
  2 commentaires
Reji G
Reji G le 17 Sep 2022
I need Temperature value(T(x,t)). an x y plot is required. Not the graph you plotted
Torsten
Torsten le 17 Sep 2022
clc;
close all;
clear all;
T1 = 300;
Ti = 350;
L = 10;
alpha = 100;
syms n t x
T = symsum((exp(((-n*pi)/(2*L))*(alpha*t)))*sin((n*pi*x)/(2*L)),n,1,20);
T = T1+4/pi*(Ti-T1)*T;
T = matlabFunction(T);
x = 0:0.01:L;
t = 0.1;
figure(1)
plot(x,T(t,x))
x = L/2;
t = 0:0.001:0.5;
figure(2)
plot(t,T(t,x))

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