Graph appears blank but the equation and code are correct.

Hi,

I'm graphing a Gaussian function that resembles the inverse impulse response, which should look like this:

However, the graph on matlab appears blank and I can't figure out the problem.

My code:

H_k_eq = @(k) (exp(-pi.*k.^2)) /  (exp(-pi.*k.^2) + exp(-pi.*(4.*k).^2));
Range = -0.5:.01:0.5;
plot(Range,H_k_eq(Range))

What is wrong with my code?

Answer 1

[Walter Roberson]

The MATLAB / operator is "matrix right division". A/B is similar to A * pinv(B) (but not exactly that.) So when you have a row vector on the left and the right of the / operator, MATLAB does what is effectively a fitting operation, returning a scalar result

H_k_eq = @(k) (exp(-pi.*k.^2)) ./  (exp(-pi.*k.^2) + exp(-pi.*(4.*k).^2));
Range = -0.5:.01:0.5;
plot(Range,H_k_eq(Range))

[Nathan]

Thank you!

Answer 2

[KSSV]

H_k_eq = @(k) (exp(-pi.*k.^2)) ./  (exp(-pi.*k.^2) + exp(-pi.*(4.*k).^2));  %<-- element by element division 
Range = -0.5:.01:0.5;
plot(Range,H_k_eq(Range))

[Nathan]

Thanks