How to terminate the MATLAB code?

I'm running the following code

n = 10000000;

a = 3.8;

x(1) = 0.5;

tic

for i=1:n

x(i+1)=a*x(i)*(1-x(i));

end

Time = toc

I wanted to set some time limit say Time = 35 s.

How can I apply time limit condition on the above code such that if Time= 35 s. The code will automatically terminate.

[Sharmin Kibria]

You can move Time=toc inside the loop and break if (Time == 35) .

Answer 1

[Davide Masiello]

n = 100000000;
a = 3.8;
x(1) = 0.5;
tic
Time = 0;
for i=1:n
    if Time > 5
        fprintf('You run out of time')
        break
    end
    x(i+1)=a*x(i)*(1-x(i));
    Time = toc;
end

You run out of time

disp(Time)

    5.0000

[Noor Fatima]

@Davide Masiello Thank you,

If there is not a for loop , can we apply time limit ?

e.g.,

tic

X = myfunction(a, n,x)

toc

[Walter Roberson]

In order to impose a time limit on a calculation without the cooperation of the code, you have to use parfeval() to run the code in a parallel pool or in a background thread pool; you can cancel() the "future" of the worker if it reaches the time limit.

Background pools were introduced relatively recently and do not require additional toolboxes. Parallel pools are older but require Parallel Computing Toolbox