Remove the 1x1 Cell Array from the Cell Array

Hey everyone,

I have the following code:

s{1} = [4 2];
s{2} = [2 1]; 
S{1} = [s{1}];
m = 1;

m = 1

for j = 1:m
    Temp_D{j} = S{j} - s{j+1};
end

Temp_D = cell2sym(Temp_D);

D{1} = Temp_D;

D{1}

ans = 

However, when I use this chunk of code as a function in my code, I get the following result :

Why do I need to do D{1}{1} To access the the array [2, 1], can I solve this problem?

[Jan]

Why do you consider this as a "problem". It is exactly, what the code instructs Matlab to do. What do you want instead?

[Ahmed Radhi]

Because I want the output to be D{1} = [2, 1], instead.

In this way, let’s assume I added one more array to D, such that D{2} = [1, 2, 0], how can I access it? Is it by D{2}{1}?

Answer 1

[Jan]

If you want D{1} = [2, 1], use:

D{1} = [2, 1]

D = 1×1 cell array
    {[2 1]}

% or equivalently
D = {[2, 1]}

D = 1×1 cell array
    {[2 1]}

Expanded:

D = {[2,1], [1,2,0]}

D = 1×2 cell array
    {[2 1]}    {[1 2 0]}

D{1}

ans = 1×2

2 1

D{2}

ans = 1×3

1 2 0

Maybe in your case:

D = Temp_D;
% not D{1} = ...

What is the purpose of cell2sym?

[Ahmed Radhi]

Thank you so much

cell2sym basically put all the arrays in the cell into one array; therefore, I can use that to put the array as D{1}.

Also, I found that since I am using a function as D{i} = “and then I call my function”, this is basically why I get a cell array at D{1}, because basically I am calling D{i} twice, once in the function and once in the main code, and so I declared the variable in the function as D.

[Jan]

Okay. Do you really want a symbolic array?

[Ahmed Radhi]

I used the cell2sym to put all the arrays in Temp_D in one array, and then I can put it as a single array in the first cell of D. So yes I want a symbolic array.