Effacer les filtres
Effacer les filtres

extracting rows from large table

8 vues (au cours des 30 derniers jours)
Mark Bodner
Mark Bodner le 30 Sep 2022
Commenté : Walter Roberson le 11 Oct 2022
I have a large table (23000000x11) and want to extract rows from the table based on values in the 5th column.
for example the data looks like:
66172 8:17 1 2 1 1 1 1 1 6 8
66842 7:17 1 3 0 1 1 1 1 1 7
.
.
.
and I want to create a smaller table with all the rows whose value of the fifth column are 0. This is of course easy to do with for loops and if statements, but takes enormous amounts of time to run. Is there a way using maybe ismember, intersect, or some other means to carry this out. I'm sure there must be. Any suggestions are appreciated.

Réponse acceptée

Walter Roberson
Walter Roberson le 30 Sep 2022
mask = YourTable{:, 5} == 0;
subset0 = YourTable(mask, :);
  3 commentaires
Siddharth Bhutiya
Siddharth Bhutiya le 10 Oct 2022
For the first line of code dot would be much faster than brace.
mask = YourTable.varName == 0; % if you know the name of your fifth variable
mask = YourTable.(5) == 0; % if you dont know the name.
Walter Roberson
Walter Roberson le 11 Oct 2022
I was curious about the timing.
In my tests, the first 5 or so {:,5} accesses were reliably much slower than the others, so I skip those in the plot.
I must admit that I do not understand why {:,5} would be 5 or 6 times slower than .(5)
format long g
YourTable = array2table(randi(9, 5000, 7), 'VariableNames', {'a', 'b', 'c', 'd', 'e', 'f', 'g'});
N = 50;
skip = 7;
time_brace = zeros(N,1);
time_named = zeros(N,1);
time_dotnum = zeros(N,1);
for K = 1 : N
tic; YourTable.(5); t=toc(); time_dotnum(K) = t;
tic; YourTable{:,5}; t=toc(); time_brace(K) = t;
tic; YourTable.e; t=toc(); time_named(K) = t;
end
subset = [time_brace(skip+1:end), time_named(skip+1:end), time_dotnum(skip+1:end)];
plot(subset);
legend({'\{:,5\}', '.e', '.(5)'})
mean(subset)
ans = 1×3
1.0e+00 * 7.27209302325581e-05 1.4046511627907e-05 1.01627906976744e-05

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by