The parfor loop cannot be run due to the way variable 'J' is used

3 vues (au cours des 30 derniers jours)
Jamais avenir
Jamais avenir le 4 Mar 2015
Commenté : Stephen23 le 5 Mar 2015
I am receiving the following error in using parfor. Is there any way to use Parfor for here?
The parfor loop cannot be run due to the way variable 'J' is used
parfor xpop = 1:Xpop
Gxm = (X(xpop,M:Nvar)-0.5*ones(1,K)) * (X(xpop,M:Nvar)-0.5*ones(1,K))';
Cos = cos(X(xpop,1:M-1)*pi/2);
J(xpop,1) = prod(Cos)*(1+Gxm);
for nobj = 1:M-1
J(xpop,nobj+1) = (J(xpop,1)/prod(Cos(1,M-nobj:M-1)))...
* sin(X(xpop,M-nobj)*pi/2);
end
end*

Réponse acceptée

Matt J
Matt J le 4 Mar 2015
Modifié(e) : Matt J le 4 Mar 2015
There is, but it seems terribly unnecessary. Everything you are currently attempting to do with parfor is abundantly vectorizable,
xpop=1:Xpop;
Gxm=sum((X(xpop,M:Nvar)-.5).^2,2);
Cos = cos(X(xpop,1:M-1)*pi/2);
tmp1=prod(Cos,2).*(1+Gxm);
tmp2=tmp1./prod(Cos(1,M-nobj:M-1));
J(xpop,1:M)=[tmp1, bsxfun(@times,tmp2, sin(X(xpop,M-1:-1:1)*pi/2) )];
  3 commentaires
Matt J
Matt J le 4 Mar 2015
Modifié(e) : Matt J le 4 Mar 2015
No, there can't be any parfor error messages. There are no for loops or parfor loops in the code I gave you.
Jamais avenir
Jamais avenir le 5 Mar 2015
That's true, It doesn't have any errors. Thank you.

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