Réponse acceptée

Image Analyst
Image Analyst le 5 Oct 2022
Modifié(e) : Image Analyst le 5 Oct 2022
Here is one way:
x = linspace(-pi, pi, 1000);
f = zeros(1, length(x));
f(abs(x) <= pi/2) = 1;
plot(x, f, 'b-', 'LineWidth', 2)
ylabel('f');
xlabel('x');
grid on;

Plus de réponses (1)

Torsten
Torsten le 5 Oct 2022
f = @(x) abs(x)<=pi/2;
x = linspace(-pi,pi,200);
plot(x,f(x))

Catégories

En savoir plus sur Simulation, Tuning, and Visualization dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by