Structure of array: deletion of null elements

In a for loop, I am reading data from a .csv file, and copying them into a structure made of several arrays, fixed number of elements (276). Depending on the structure array called f_avg, I would like to keep or delete the whole structure element. For instance, if f_avg(k, 1)== 0, I would like to delete the k_th element of each array belonging to that structure. To do so, I tried the following (see below), getting the error "The logical indices contain a true value outside of the array

bounds.

Error in data_analysis_multiple_files (line 65)

exp_value = exp_value(exp_value.f_avg(:, 1)~=0)". Thank you in advance for your help.

exp_value = exp_value(exp_value.f_avg(:, 1)~=0);

[Jan]

What do you call "the whole structure element"?

exp_value is the struct, correct? Which dimensions does it have? Which size has exp_value.f_avg? The error message means, that exp_value.f_avg(:, 1) has more elements than exp_value.

[Andrea Giordano]

Sorry, my bad. Yes, exp_value is the structure i mention (1 x 1 structure), 7 fields:

f_avg (276 x 3) double

f_std (276 x 3) double

t_avg (276 x 3) double

t_std (276 x 3) double

aoa (276 x 1) double

vel (276 x 1) double

inflation (276 x 1) double

Answer 1

[Jan]

S      = exp_value;   % Just for readability
remove = (S.f_avg(:, 1) == 0);
fields = setdiff(fieldnames(S), {'f_avg'});  % All fields but f_avg
for k = 1:numel(fields)
    S.(fields{k})(remove, :) = [];
end

Slightly shorter, but with strange loop over a cell string:

S      = exp_value;   % Just for readability
remove = (S.f_avg(:, 1) == 0);
fields = setdiff(fieldnames(S), {'f_avg'});  % All fields but f_avg
for F = fields
    S.(F)(remove, :) = [];
end

Answer 2

[Chunru]

exp_value(exp_value.f_avg(:, 1)==0) = [];

[Andrea Giordano]

Matrix index is out of range for deletion.

Error in data_analysis_multiple_files (line 66)

exp_value(exp_value.f_avg(:, 1)==0) = [];