How to write a discontinuous signal equation in matlab?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Tejas Nagotkar
le 12 Oct 2022
Commenté : Tejas Nagotkar
le 12 Oct 2022
x1=0.2*(sin(2*pi*150*t)) = 0.05<=t<=0.1
x2=0.4*(sin(2*pi*50*t)) = 0.15<=t<=0.25
x3=(sin(2*pi*10*t)) = 0<=t<=0.3
x=x1+x2+x3;
How to write equation in matlab so that i can get the following plots?

0 commentaires
Réponse acceptée
Davide Masiello
le 12 Oct 2022
Modifié(e) : Davide Masiello
le 12 Oct 2022
t = 0:0.001:0.3;
x1 = 0.2*sin(2*pi*150*t); x1(t<=0.05 | t>=0.1) = 0;
x2 = 0.4*sin(2*pi*50*t); x2(t<=0.15 | t>=0.25) = 0;
x3 = sin(2*pi*10*t);
x = x1+x2+x3;
subplot(2,2,1)
plot(t,x1)
subplot(2,2,2)
plot(t,x2)
subplot(2,2,3)
plot(t,x3)
subplot(2,2,4)
plot(t,x)
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Subplots dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
