How Can I establish a raking scale of variables within an array?

2 vues (au cours des 30 derniers jours)
Fed
Fed le 10 Mar 2015
Commenté : Andrew Newell le 10 Mar 2015
Hi everyone!
This is my array:
a = [0 0 1 3];
I want to define which is the highest value and therefore define a rank in this way:
a_ranking = [4 4 2 1];
where the 4th value is 1 because it was the most chosen.
This is how I found the max values (first and second):
maxH = max(a);
FirstH = find(a == maxH);
secMaxH = max(a(a~= maxH));
SecondH = find(a == secMaxH);
so, I know the in the 4th position there is the highest value and in the third the second one, but how Can I associate the value 1 and 2 respectably to the the third and fourth position of the array.
But I am lost when I have to re-write the array in this way
a_ranking = [4 4 2 1];
I don't know how to reach this point!
Basically, I need to create a array with the same length of the one I am using but indicating the ranking scale of the chosen answer. Is that clear?
Please help me!
  1 commentaire
Andrew Newell
Andrew Newell le 10 Mar 2015
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Andrew Newell
Andrew Newell le 10 Mar 2015
Modifié(e) : Andrew Newell le 10 Mar 2015
Your ranking scheme is somewhat unusual because usually the ranking does not have any gaps in it. That would be easy to implement using unique, which not only finds the unique elements and sorts them but returns indices that are, in effect, ranks:
[~,~,a_ranking] = unique(max(a)-a)
a_ranking =
3
3
2
1
Are you sure this isn't what you want?
  2 commentaires
Fed
Fed le 10 Mar 2015
thank you! I've never used the function unique. In this way it is much simpler. Since I have to multiple each element of ic for a different weight on the basis of their ranking, I thought it could be better to consider the last two values as 4 instead of 3, in order to give to them the less weight. do you understand?
And by the way your solution is much better than mine :)
Andrew Newell
Andrew Newell le 10 Mar 2015
You're welcome. I don't know which weighting scheme would be better - depends on the application. If this solves the problem, can you click on "Accept this answer"?

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