Conversion of a matrix into multiple column vectors

If we have a matrix A=[1 2 ; 3 4 ; 5 6] then it will be converted to vectors like x1= [1 3 5] x2= [2 4 6]

Answer 1

[Stephen23]

If you know how many columns you want, then you can simply assign them in code like this:

>> A = [1,2;3,4;5,6];
>> X1 = A(:,1);
>> X2 = A(:,2);

If you have many columns, or an unknown sized matrix, then you can split it up using num2cell with the second optional argument:

>> B = num2cell(A,1);
>> B{1}
ans =
     1
     3
     5

>> B{2}
ans =
     2
     4
     6

Accessing the contents of the cell array is simple and efficient using indexing:

https://www.mathworks.com/help/matlab/matlab_prog/access-data-in-a-cell-array.html

Accessing dynamically named variables like x1, x2, x3, etc. is not recommended, because it forces you into writing slow, complex, obfuscated, buggy code that is hard to debug. Read this to know why:

https://www.mathworks.com/matlabcentral/answers/304528-tutorial-why-variables-should-not-be-named-dynamically-eval

[Subham Burnwal]

Thank you Sir

[Subham Burnwal]

Thank you Sir

[Alpha Bravo]

x=[1 2 3; 4 5 6; ... ;...; ...]; % some m x n matrix

a = unique(x);

out = [a,histc(x(:),a)];% upto here unique frequencies

x1 = out(:,1);

x2 = out(:,2);

[tbl,chi2stat,pval] = crosstab(x1,x2);

disp(chi2stat);

disp(pval);

chi2stat 1.9866e+04

p 0.3317

is the code above correct? then what to interpret of the matrix

[Stephen23]

"is the code above correct?"

I don't know. What do you expect that code to do?

[Alpha Bravo]

kindly;

1. reduce m x n matrix to its frequency count
2. crosstab into 2x 2
3. subject those to compute chi2 and p
4. interpret that result
5. that is, to find the chi2, and p of the given matrix; the goodness of fit test

Answer 2

[Giorgos Papakonstantinou]

x1 = A(:,1).';

x2 = A(:,2).';