Why does the code return an additional answer value that I have not asked for?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
First I defined a function:
function [p,q] = quadratic_formula(a, b, c)
p = (-b + sqrt((b)^2-4*a*c))/(2*a)
q = (-b - sqrt((b)^2-4*a*c))/(2*a)
end
After that I called the fuction with varying values. Every time it returns an answer value that I haven't asked for. For example,
quadratic_formula(5, 8, 3)
returns following:
p =
-0.6000
q =
-1
ans =
-0.6000
I don't want this answer value. Why does it return that equal to the value of 'p'?
0 commentaires
Réponses (2)
Davide Masiello
le 20 Oct 2022
Modifié(e) : Davide Masiello
le 20 Oct 2022
That is because you call the function without assigning it to a variable.
Therefore Matlab assigns it to a variable called ans, which can accept only one value, i.e. the first one (or p in your case).
So, the first 2 values that appear are printed from within the function (because you didn't use semicolons).
Then it also shows ans because you also call the function without semicolons.
A better way of doing this in Matlab is
[p,q] = quadratic_formula(5, 8, 3)
function [p,q] = quadratic_formula(a, b, c)
p = (-b + sqrt((b)^2-4*a*c))/(2*a);
q = (-b - sqrt((b)^2-4*a*c))/(2*a);
end
0 commentaires
Karen Yadira Lliguin León
le 20 Oct 2022
you need to put ';' at the end of the line to stop . Change these lines
p = (-b + sqrt((b)^2-4*a*c))/(2*a);
q = (-b - sqrt((b)^2-4*a*c))/(2*a);
0 commentaires
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!