I can't figure out why am not getting a plot on my code
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Write a MATLAB code for plot original and transformation function of
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');
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Réponses (1)
Chunru
le 25 Oct 2022
If you put the script and local function ga in the same file, then local functions should be placed at the end of the files as shown below. You can also put the local function in a separate file,
figure;
tmin=-3;tmax=8;N=100;
dt=(tmax-tmin)/N; t=tmin+dt*[0:N]';
g0=ga(t);g1=-3*ga(4-t);
subplot(2,1,1);p=plot(t,g0,'k');set(p,'LineWidth',2);grid;
ylabel('g(t)');
title('(a)-g(t)=-2,t<-1,2t,-13')
subplot(2,1,2);p=plot(t,g1,'k');set(p,'LineWidth',2);grid;
xlabel('t');ylabel('-3g(4-t');
function y=ga(t);
y = -2*(t<=-1)+2*t.*(-1<t&t<=1)+(3-t.^2).*(1<t&t<=3)-6*(t>3);
end
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