How to add tolerance to iteration with if statement
9 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Bethany Sinclair
le 27 Oct 2022
Réponse apportée : Chunru
le 27 Oct 2022
I have a Gauss-seidel iteration code, which works to 99 iterations with a relaxation factor. However, when I put an if statement in (no other changes), to say if the different between iteration a^x+1-a^x is less than a certain tolerance say 0.1 then stop the iteration sequence before the specified 99 iterations.
Any help to spot any issues would be appreciated!
a2(1,1)=0;
b2(1,1)=0;
c2(1,1)=0;
R2=0.3;
for i=1:99
if a2(i+1,1)-a2(i,1)<0.1
a2(i+1,1)=(1-R2)*a2(i,1)+R2*(4-b2(i,1)-c2(i,1));
b2(i+1,1)=(1-R2)*b2(i,1)+R2*(2*a2(i+1,1)+4*c2(i,1)-33)/3;
c2(i+1,1)=(1-R2)*c2(i,1)+R2*(3*a2(i+1,1)-2*b2(i+1,1)-2)/2;
end
end
figure(5);
plot(a1);
hold on
plot (b1);
plot (c1);
0 commentaires
Réponse acceptée
Chunru
le 27 Oct 2022
x(1,1)=0; %Initial guess, x=0
y(1,1)=0; %Initial guess, y=0
z(1,1)=0; %Initial guess, z=0
R=0.3; %relaxation factor
for i=1:99 %99 is the number of iterations
x(i+1,1)=(1-R)*x(i,1)+R*(4-y(i,1)-z(i,1)); %what multiplied with R is the "new" x value produced by the equation
y(i+1,1)=(1-R)*y(i,1)+R*(2*x(i,1)+4*z(i,1)-33)/3; %what multiplied with R is the "new" y value produced by the equation
z(i+1,1)=(1-R)*z(i,1)+R*(3*x(i,1)-2*y(i,1)-2)/2; %what multiplied with R is the "new" z value produced by the equation
if abs(x(i+1)-x(i)) < 0.1
break
end
end
plot(x);
hold on
plot(y);
plot(z);
0 commentaires
Plus de réponses (1)
Chunru
le 27 Oct 2022
% if a2(i+1,1)-a2(i,1)<0.1
% change the above to:
if abs(a2(i+1,1)-a2(i,1))<0.1
3 commentaires
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
