Maximum value of matrix

1 vue (au cours des 30 derniers jours)
mingcheng nie
mingcheng nie le 29 Oct 2022
Commenté : mingcheng nie le 29 Oct 2022
Hi there,
If we have a complex matrix A, size of (N,M), is there any efficient way to keep the maximum 6 absolute values in A and set others to be zeros? like abs(A(n,m)), keep the top6 biggest one, then set rest to 0.
Really appreciate for anyone leave a comment.

Réponse acceptée

Kevin Holly
Kevin Holly le 29 Oct 2022
% Generate random matrix
N = 34;
M = 23;
A = rand(N,M);
% Sort from highest to lowest
values = sort(abs(A(:)), 'descend')
values = 782×1
0.9998 0.9985 0.9980 0.9971 0.9965 0.9962 0.9950 0.9924 0.9914 0.9913
% top 6
values(1:6)
ans = 6×1
0.9998 0.9985 0.9980 0.9971 0.9965 0.9962
values(6)
ans = 0.9962
B = (A>=values(6)).*A
B = 34×23
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.9980 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0.9985 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
imshow(B)
  3 commentaires
Kevin Holly
Kevin Holly le 29 Oct 2022
I would appreciate it if you could accept this answer.
mingcheng nie
mingcheng nie le 29 Oct 2022
sure definitely

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