Effacer les filtres
Effacer les filtres

how to avoid repeat numbers in a row

1 vue (au cours des 30 derniers jours)
imola
imola le 19 Mar 2015
Commenté : imola le 19 Mar 2015
Dear All,
I have this row
A=[1 2 3 4 5 6];
I tried to find random permutation on the vector but in many cases I got a row with repetition numbers for example
z=[1 5 2 4 1 5];or z=[1 5 2 4 1 1];
I want to avoid the repetition in this code but it is totally wrong, at first I should assign the missing numbers in such way, here is [3 6].
zc=[3 6 ];
e=size(zc,2);
z=[1 5 2 4 1 5];
for i=1:6
z(i)==z
s = find((z(i)==z) == 1)
ss=size(s,2);
for j=2:ss
for k=1:e
z(j)=zc(k)
end
end
end
I don't want to use a function from matlab to get the permutation, I need to fix my row or any permutation exchange file like (perm file ). If anyone help me for it and save me I will be grateful.
regards,
Imola
  2 commentaires
Guillaume
Guillaume le 19 Mar 2015
I don't want to use a function from matlab to get the permutation:
Does that mean that you've written your own uniform number generator? Otherwise, at some point you'll have to use rand, so you just might as well use randperm.
imola
imola le 19 Mar 2015
yes exactly I used randperm.

Connectez-vous pour commenter.

Réponse acceptée

Sean de Wolski
Sean de Wolski le 19 Mar 2015
[~,x] = sort(rand(1,6))
No randperm
  1 commentaire
imola
imola le 19 Mar 2015
I m sorry Sean,
but I wanted to accept Guillaume answer and by mistake I chose yours, how I change it because his answer was great.
regards

Connectez-vous pour commenter.

Plus de réponses (1)

Guillaume
Guillaume le 19 Mar 2015
It seems to me that your effort would be better spent on fixing the code that generate these invalid permutation rather than fixing the permutation afterward.
Anyway, one way to do what you want:
z = [1 5 2 4 1 1];
zc = [3 6];
%build a cell array containing the indices of repeated values:
repindices = accumarray(z', 1:numel(z), [], @(v) {v(2:end)'})';
%convert cell array into vector:
repindices = [repindices{:}];
%replace values at indices by replacement:
z(repindices) = zc
  4 commentaires
Guillaume
Guillaume le 19 Mar 2015
If you're asking how to build zc:
zc = setdiff(1:6, z)
imola
imola le 19 Mar 2015
Dear Guillaume,
I'm so sorry, by mistake I chose Sean's answer. Forgave me.
Regards

Connectez-vous pour commenter.

Catégories

En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by