how to avoid repeat numbers in a row

Dear All,
I have this row
A=[1 2 3 4 5 6];
I tried to find random permutation on the vector but in many cases I got a row with repetition numbers for example
z=[1 5 2 4 1 5];or z=[1 5 2 4 1 1];
I want to avoid the repetition in this code but it is totally wrong, at first I should assign the missing numbers in such way, here is [3 6].
zc=[3 6 ];
e=size(zc,2);
z=[1 5 2 4 1 5];
for i=1:6
z(i)==z
s = find((z(i)==z) == 1)
ss=size(s,2);
for j=2:ss
for k=1:e
z(j)=zc(k)
end
end
end
I don't want to use a function from matlab to get the permutation, I need to fix my row or any permutation exchange file like (perm file ). If anyone help me for it and save me I will be grateful.
regards,
Imola

2 commentaires

Guillaume
Guillaume le 19 Mar 2015
I don't want to use a function from matlab to get the permutation:
Does that mean that you've written your own uniform number generator? Otherwise, at some point you'll have to use rand, so you just might as well use randperm.
imola
imola le 19 Mar 2015
yes exactly I used randperm.

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 Réponse acceptée

Sean de Wolski
Sean de Wolski le 19 Mar 2015
[~,x] = sort(rand(1,6))
No randperm

1 commentaire

I m sorry Sean,
but I wanted to accept Guillaume answer and by mistake I chose yours, how I change it because his answer was great.
regards

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Plus de réponses (1)

Guillaume
Guillaume le 19 Mar 2015
It seems to me that your effort would be better spent on fixing the code that generate these invalid permutation rather than fixing the permutation afterward.
Anyway, one way to do what you want:
z = [1 5 2 4 1 1];
zc = [3 6];
%build a cell array containing the indices of repeated values:
repindices = accumarray(z', 1:numel(z), [], @(v) {v(2:end)'})';
%convert cell array into vector:
repindices = [repindices{:}];
%replace values at indices by replacement:
z(repindices) = zc

4 commentaires

Guillaume
Guillaume le 19 Mar 2015
Note that if you don't randomise which of the duplicates (my code above always pick the first ones) or the order of the replacements, then the distribution of the generated permutations is not uniform
imola
imola le 19 Mar 2015
Dear Guillaume,
Thank you very much that's was great, I really appreciate that, you save may day, but for zc is there any way to now the repeated numbers in advance, because I will have a lot of rows in my code to change the repetition numbers in them.
Thanks
Imola
If you're asking how to build zc:
zc = setdiff(1:6, z)
imola
imola le 19 Mar 2015
Dear Guillaume,
I'm so sorry, by mistake I chose Sean's answer. Forgave me.
Regards

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