Nul characters and wildcards in regexp

1 vue (au cours des 30 derniers jours)
Brig
Brig le 23 Mar 2015
It seems to be the case that when a regular expression encounters the pattern
[0 46 0]
it always matches everything after it.
Is this a side effect explainable in any way, or just a bug?
Example:
K>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
The expected answer would be [] because 41 should not match the 40 in the pattern.
  1 commentaire
per isakson
per isakson le 23 Mar 2015
Modifié(e) : per isakson le 23 Mar 2015
I call it a bug. Why not report it to tech-support whether it is a real problem to your projekt or not.

Connectez-vous pour commenter.

Réponses (1)

Tijs Van Oevelen
Tijs Van Oevelen le 10 Mai 2016
Hi,
this bug is probably already fixed. I tested your example in several versions of Matlab:
  • in R2013b:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
  • in R2015a:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
2
  • in R2016a:
>> regexp(char([0 0 1 0 41 41 41 41 41 41]),char([0 '.' 0 40 40 40 40]))
ans =
[]

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by