Build Matrix from X and Y Coords and Corresponding Values
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Hello,
I have three vectors and I want to construct a matrix from them.
- 'a' is a vector of length n, containing magnitude data.
- 't' is a vector (also length n) of time indices at which the samples in 'a' occur.
- 'f' is a vector (length m) of frequency indices at which the samples in 'a' occur.
t = 1:1:2500; % Vector of sample indices
f = 1:1:100; % Vector of frequency indices
a = rescale(square(t)); % Vector of magnitude values
How can I construct matrix 'M' with each value in 'a' occurring at the corresponding coordinate in (t, f), and all other indices in 'M' = 0?
- Using diag(a) does not work, because 't' and 'f' are of different lengths. I can resample or interpolate 'M' to change the resulting square matrix into a rectangular one, but this corrupts the data. I do not want to reduce the number of rows of M by decimation, but rather by allowing 'r' values of m to occupy each row.
% diag and resamp method - does not work.
M = diag(a);
% ratio of 't' to 'f'
r = length(t) / length(f);
% resample 'M' to dimensions of [length(f) x length(t)]
M_rect = resample(M, 1, r, 'Dimension', 2);
- I have tried simply writing element-by-element into 'M' in a for-loop, however for obvious reasons, this leaves me with a square matrix of either nxn. Essentially this is identical to diag(a).
% Single index Loop method - does not work
for i = 1:length(t)
M(i, i) = a(i);
end
- I have tried writing element-by-element into 'M' in two nested for-loops with row and column indices, however this results in 'M' having correct dimensions, but the values of 'a' fill every column. Essentially this is identical to diag(a).
% Dual index Loop method - does not work
for i = 1:length(t)
for j = 1:length(f)
M(j, i) = a(i);
end
end
This seems like it should be quite simple, but it's been wrecking my head. Any help would be most appreciated.
Thanks in advance,
Ben
1 commentaire
Matt J
le 9 Nov 2022
What are the intended dimensions of M? How is it that "f is a vector (length m) of frequency indices at which the samples in 'a' occur" but length(f)~=length(a)?.
Réponse acceptée
Matt J
le 9 Nov 2022
Modifié(e) : Matt J
le 9 Nov 2022
Generally speaking, if you have a list of (t,f) coordinates with corresponding values a, you can use accumarray, e.g.,
t=[1,2,3]';
f=[2,2,5]';
a=rand(1,3)'
M=accumarray([t,f],a,[5,6])
M=sparse(t,f,a,5,6);
full(M)
3 commentaires
Matt J
le 15 Nov 2022
Modifié(e) : Matt J
le 15 Nov 2022
These variables are never used
f = linspace(f1, f2, nf); % Vector of frequencies (Hz)
a = rescale(square(t)); % Vector of magnitude values
so I have had to add some "if" statements to pad extra zeros or trim end samples in cases where f_indices ends up being the wrong length
What should happen if it is the wrong length? Should f_indices grow/shrink to 2500 or should t change length to accomodate f_indices?
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