PCA scaling and centering documentation wrong?
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
The pca() documentation says that the raw data is automatically centered at the start of the process. If true, then pca(X) should be equal to pca(Y), where Y = centered data. But they're not (specific data below). Additionally, when I use either eig() or svd() to compute the principal components, I can only get them to match the pca output when I first manually center the data before using pca(). Ultimately my question is simply how do I correctly calculate the principal components of raw data? I.e. do I need to manually center and scale it first? Only manually center? Only manually scale?
Sample data: X =
1.0000 -3.0000 -1.0000; 2.0000 -2.0000 -0.5000; 3.0000 -0.5000 0.2500; 4.0000 2.0000 1.0000; 5.0000 5.0000 2.5000;
Centering X -> Y= -2.0000 -3.3000 -1.4500; -1.0000 -2.3000 -0.9500; 0 -0.8000 -0.2000; 1.0000 1.7000 0.5500; 2.0000 4.7000 2.0500;
pca(X) = -0.7360 -0.6037 -0.3062; -0.6688 0.7186 0.1907; -0.1049 -0.3452 0.9327;
pca(Y) =
0.4058 0.8414 0.3569
0.9124 -0.3960 -0.1036
0.0542 0.3676 -0.9284
svd(Y) = 0.4058 0.9124 0.0542; 0.8414 -0.3960 0.3676; 0.3569 -0.1036 -0.9284;
eig(cov(Y)) = 0.0542 0.9124 0.4058; 0.3676 -0.3960 0.8414; -0.9284 -0.1036 0.3569; ^this is the same output just in a different order.
0 commentaires
Réponses (2)
Sagar
le 9 Août 2015
You got it little wrong. When you do PCA(Y), by default, PCA again centers the data. So if you want to get the same values as PCA(X), use 'centered', 'off' name-value pair option: PCA_of_Y = PCA (Y, 'centered', 'off'); Now it will definitely be equal to PCA(X).
0 commentaires
the cyclist
le 26 Juin 2019
Modifié(e) : the cyclist
le 8 Août 2022
Answering a gazillion years after-the-fact, because I just turned this up in my own search.
X = [1.0000 -3.0000 -1.0000;
2.0000 -2.0000 -0.5000;
3.0000 -0.5000 0.2500;
4.0000 2.0000 1.0000;
5.0000 5.0000 2.5000];
Y = X - mean(X);
pca(X)
pca(Y)
both give the same PCA results (as of when I answered this).
So, either something got fixed, or you made a mistake.
0 commentaires
Voir également
Catégories
En savoir plus sur Dimensionality Reduction and Feature Extraction dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!