Embedded MATLAB FUnction as elaboration block only

Hi,

I have to made an Embedded MATLAB Function which puts input in "for" and/or "if" loop(s) and takes output from loop conditions.

The real problem, infacts, is that Embedded MATLAB Function wants output DIRECTLY connected to input only.

Thanks for kindness

[Walter Roberson]

There is no such thing as an if loop.

Answer 1

[Kaustubha Govind]

From what I understand, I think the real reason may be because you do not pre-allocate memory for the output. See Assign Variables Explicitly Before Using Them.

For example:

function X = fcn %#eml

N = 5;
X = zeros(1,N); % explicitly pre-allocate output
for i = 1:N
   if mod(i,2) == 0
      X(i) = i;
   else
      X(i) = 0;
   end
end

If this is not the answer you are looking for, could you please post a simple code snippet so it is easier to understand the question?

Answer 2

[cyberdyne]

The problem is this: I've two changing inputs to EML; call them s1 and s2. They are two definite integrals each of them from t0 to t0+Ts (where Ts is clock time and t0 is the starting istant).Therefore they are two successions of numbers. I want that when this two inputs have the same value, output is that value. I try with following code:

function y=fcn (s1, s2)

m=length(s2);
n=length(s1);
for i=1:n
for j=1:m
  if s1(i)==s2(j)
    y=s1(i);
     break
  end
end
end

but EML wants that y must be ALWAYS directly bind to inputs. It doesn't want loop conditions.

Answer 3

[Kaustubha Govind]

As I described before, you need to pre-allocate 'y' in your code. Since in this case, y is a scalar, you can simply have:

function y=fcn (s1, s2)

y = 0; % Pre-allocate y

m=length(s2);
n=length(s1);
for i=1:n
for j=1:m
  if s1(i)==s2(j)
    y=s1(i);
     break
  end
end
end

[cyberdyne]

But in this way while s1(i) is not equal to s2(j), y=0 continuously. Instead i want that there is an output when s1==s2 only.

[Kaustubha Govind]

Unfortunately, it isn't possible to NOT have an output assigned. The best you can do is assign y=NaN, which gives you some indication of when s1(i) is not equal to s2(j).

[cyberdyne]

Therefore if i take as "else" condition:

else y=NaN;

it means that when s1 is not equal to s2 it returns NaN-elements ?

[Kaustubha Govind]

Sure, you could do that. Just make sure that you pre-allocate 'y' before the for-loops though.