哪位大神能帮忙解决了这个问题啊 新手求帮助。

clear all

r = 5;

g = 9.8;

thetaC = pi/6;

thetaB = pi;

xb = r*(thetaB-sin(thetaB));

yb = r*(1-cos(thetaB));

xc = r*(thetaC-sin(thetaC));

yc = r*(1-cos(thetaC));

syms x

a = int((1-cos(x))/(cos(thetaC)-cos(x)),thetaC,thetaB);

t = sqrt(r/g)*a

B = [xb yb]

C = [xc yc]

运行之后 t = Inf;

理论来说 t 有值的，没有达到无穷大。

Answer 1

[riwobe]

clear;close all;
r = 5;
g = 9.8;
thetaC = pi/6;
thetaB = pi;

xb = r*(thetaB-sin(thetaB));
yb = r*(1-cos(thetaB));
xc = r*(thetaC-sin(thetaC));
yc = r*(1-cos(thetaC));
syms x
a=(1-cos(x))/(cos(thetaC)-cos(x));
a=matlabFunction(a);
a=quadgk(a,thetaC,thetaB)
t = sqrt(r/g)*a