How would this be solved

Question in PDF

[Matt J]

By you.

Answer 1

[Walter Roberson]

The tangent line of a curve has a tan() that is dy/dx, and it passes through the point of interest. Remember y = m*x + b and m = dy/dx and b is the value needed to get the straight line to pass through (x,y)

Answer 2

[Catalytic]

Remember that the vector derivative of a parametric curve is tangent to the curve -

syms r(theta)

r(theta)=[2+3*cos(2*theta);
          -5-sin(theta/3)];

diff(r) %tangent vector

ans(theta) =