# Using a quiver function draw a plot

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Hyo Yun on 21 Nov 2022
Commented: Voss on 21 Nov 2022
I am trying to use a quiver function to draw a plot from -1 <= x,y <= 1
So far, for my code, I have...
syms x y z
u = @(x,y) y / (x.^2 + y.^2);
v = @(x,y) -x / (x.^2 + y.^2);
[x,y] = meshgrid(-1:1, -1:1);
quiver(x,y,u,v,0)
But I am getting an error saying, "Error using quiver, Input arguments must be numeric or objects which can be converted to double"
u and v are the i and j component of a vector I need to plot from -1 to 1. How do I plot this graph?

Voss on 21 Nov 2022
u = @(x,y) y ./ (x.^2 + y.^2); % use ./ instead of /
v = @(x,y) -x ./ (x.^2 + y.^2);
[x,y] = meshgrid(-1:1, -1:1);
quiver(x, y, u(x,y), v(x,y), 0) % evaluate u and v at (x,y) ##### 2 CommentsShowHide 1 older comment
Voss on 21 Nov 2022
You're welcome!

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