Generate inner values of y for each x based on n

1 vue (au cours des 30 derniers jours)
Saim Ehtesham
Saim Ehtesham le 25 Nov 2022
Commenté : Saim le 25 Nov 2022
I have the following code:
clear all
clc
n = 4; % number of divisions on the boundary
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
y2_x1 = -sqrt(1-( (x1.^2)/4 ) );
x2 = linspace(-2,0,n);
y1_x2 = sqrt(1-( (x2.^2)/4 ) );
y2_x2 = -sqrt(1-( (x2.^2)/4 ) );
x = [x1 x1 x2 x2];
y = [y1_x1 y2_x1 y1_x2 y2_x2];
scatter(x,y)
Now, is there a way to generate the inner values of y with respect to x?
For example, as we can see in the plot, an ellipse is formed, but the points are on the boundaries, I want points within the ellipse as well, such that it uses the values of x and y already calculated and connects the y values to x like at x = 0, y = 1.0000,0.9428,0.7454,0 and at next x on both positive and negative side (x = +-0.6667), y = 0.9428,0.7454,0 so on and so forth till x = +-2
But most importantly, it all stays connected, so that all I change is the value of n and the inner points are generated.
Thanks

Réponse acceptée

KSSV
KSSV le 25 Nov 2022
clc; clear all ;
clear all
clc
n = 4; % number of divisions on the boundary
x1 = linspace(0,2,n);
y1_x1 = sqrt(1-( (x1.^2)/4 ) );
y2_x1 = -sqrt(1-( (x1.^2)/4 ) );
x2 = linspace(-2,0,n);
y1_x2 = sqrt(1-( (x2.^2)/4 ) );
y2_x2 = -sqrt(1-( (x2.^2)/4 ) );
x = [x1 x1 x2 x2];
y = [y1_x1 y2_x1 y1_x2 y2_x2];
scatter(x,y)
% Arrange ellipe points properly
xCenter = mean(x);
yCenter = mean(y);
angles = atan2d(y - yCenter, x - xCenter);
[sortedAngles, sortOrder] = sort(angles);
x = x(sortOrder);
y = y(sortOrder);
[X,Y] = meshgrid(linspace(min(x),max(x)),linspace(min(y),max(y))) ;
Z = zeros(size(X)) ;
idx = inpolygon(X,Y,x,y) ;
Z(idx) = 1 ;
pcolor(X,Y,Z)
  4 commentaires
Saim
Saim le 25 Nov 2022
Thanks a lot for the clarification
Is it possible to use the values of X and Y that you generated in a delaunay connection?
Saim
Saim le 25 Nov 2022
Also, is it possible to reduce or increase the points within the ellipse?

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Spatial Search dans Help Center et File Exchange

Produits


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by