Create a loop with condition

1 vue (au cours des 30 derniers jours)
wissal zaher
wissal zaher le 29 Nov 2022
Commenté : wissal zaher le 30 Nov 2022
I want to create a loop that generate random intial values x0 as (2,1) vectors within a [-5,5] range.
Each initial value x0 will give out an output U, some values give out U = NaN (calculated with a controller)
I want the loop to keep running for all the values with U not equal NaN and save them in an array Xset
The values with U = NaN can be disqualified
I would appreciate any help

Réponse acceptée

David Hill
David Hill le 29 Nov 2022
Does not seem like you need random values, but rather all values between -5 to 5
[x,y]=meshgrid(-5:.001:5);%generates all x0 pairs (x;y) within -5 to 5 with .001 step.
i=1;
for k=1:numel(x)
U=%some function with [x(k);y(k)] input
if ~isnan(U)
Xset(:,i)=[x(k);y(k)];
i=i+1;
end
end
  3 commentaires
David Hill
David Hill le 29 Nov 2022
[x,y]=meshgrid(-5:.001:5);
xset=[];
for k=1:numel(x)
u = mpc.evaluate([x(k);y(k)]);
if ~any(isnan(u))
xset=[xset,k];
end
end
T_solve=100;
Xset=[];Uset=[];
for k=1:length(xset)
x0=[x(xset(k));y(xset(k))];
for kk=1:T_solve
u = mpc.evaluate(x0);
x1=A*x0+B*u(1);
x0=x1;
Xset=[Xset x0];
Uset=[Uset u];
end
end
wissal zaher
wissal zaher le 30 Nov 2022
thank you a lot !

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange

Produits


Version

R2022a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by