How do I exit a for loop after logical index is found true in an array?

I would like to exit a loop if the result is set to true in the for loop. But it always returns false if I use 'continue'. How do I resolve this?

% check if trajectory goes through the zone
result = false;
for i = 1:length(xNormalized)
    if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
        (yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
        result = true;
    end
    % continue;
end

Answer 1

[VBBV]

use inside the if-end statement

% check if trajectory goes through the zone
result = false;

for i = 1:length(xNormalized)
    if (xNormalized(i) > xEdge(1) && xNormalized(i) < xEdge(2)) && ...
        (yNormalized(i) > yEdge(1) && yNormalized(i) < yEdge(2))
        result = true
        break  % use inside the if - condition
    end
     
end

[VBBV]

If you use outside the if condition the result state may not be saved to true if this for loop is nested inside another loop which means it will restore the result state back to false. I presume, this for loop is present inside another loop, thats why result flag is being set to false again.

If you want to avoid reuslt to set false, you need to place the result flag outside of all nested loops.

[Atanu]

Thank you! I was using outside the if statement and that did not work. It works if I use inside if as you suggested. By the way, this for loop is the outermost loop.

Answer 2

[Steven Lord]

continue exits the current iteration and proceeds to the next iteration.

break exits the loop entirely.

[Atanu]

Both 'break' and 'continue' sets the result to default 'false'. I tried with both of them.