How to keep only a new modification in an array using for loop?

Hello, I have an array named 'a' cocsists of ones and zeros. What I want is

If an entry is zero , make it 1 and store the whole array, then move to the next term and if the elemnt is 1 store the array as it is and move to the next element in the array. I have tried in the code below but gives me a different answer. If anyone can help me in this.

a=[1 0 0 1 1 0 0 1 0];
i=1;
new=[];
for j=1:9
    if a(i)==0
        a(i)=1;
        new(i,:)= a;
    else
        new(i,:)=a;
    end
    i=i+1
end

output of the above code

1	0	0	1	1	0	0	1	0
1	1	0	1	1	0	0	1	0
1	1	1	1	1	0	0	1	0
1	1	1	1	1	0	0	1	0
1	1	1	1	1	0	0	1	0
1	1	1	1	1	1	0	1	0
1	1	1	1	1	1	1	1	0
1	1	1	1	1	1	1	1	0
1	1	1	1	1	1	1	1	1

What I want is

desired output=[1	0	0	1	1	0	0	1	0
1	1	0	1	1	0	0	1	0
1	0	1	1	1	0	0	1	0
1	0	0	1	1	0	0	1	0
1	0	0	1	1	0	0	1	0
1	1	1	1	1	1	0	1	0
1	0	0	1	1	0	1	1	0
1	0	0	1	1	0	0	1	0
1	0	0	1	1	0	0	1	1

Answer 1

[Jan]

a   = [1 0 0 1 1 0 0 1 0];
new = repmat(a, numel(a), 1);
for j = 1:numel(a)
    if new(j, j) == 0
        new(j, j) = 1;
    end
end

Alternatively:

a   = [1 0 0 1 1 0 0 1 0];
na  = numel(a);
new = zeros(na, na);
for j = 1:na
    new(j, :) = a;
    new(j, j) = 1;
end

The variables i and j have the same value in your code, so you can omit this redundant information.

Instead of modifying the original vector a, only the value in the output is changed in my code.

A simpler method to get the same output:

a   = [1 0 0 1 1 0 0 1 0];
new = a | eye(numel(a));

[lilly lord]

Thank you very much