loop not storing, or running through all values
7 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I dont really know what im doing with MATLAB so cant work out whats wrong.
Im trying to make a loop that will use a function I have made to calculate the seasonal cycle and its range at each location within an area (latitude and longitude) :
function seasonal_cycle = calc_seasonal_cycle(sst,time)
nharm = 1;
year_length = 365.25;
cutoff = 0;
[r_sst,c_sst] = size(sst);
[r_time,c_time] = size(time);
if (r_sst > r_time)
sst = sst.' ;
end
ix_n = find(~isnan(sst));
if isempty(ix_n)
timeseries = NaN;
disp('Input data is all NaN')
end
if length(ix_n) < 2
seasonal_cycle = NaN;
disp('Input data mostly NaN')
end
sst_good = sst(ix_n);
time_good = time(ix_n);
[amplitude,phase,frac,offset,yy] = fit_harmonics(sst_good,time_good, nharm, year_length, cutoff); % using fit_harmonics function to fit cosine
seasonal_cycle = offset + amplitude .* cos(2 .* pi .* (time_g/year_length) + phase); % equation for cycle
end
loop:
[nr,nc,nt] = size(sst);
cycle_range = NaN(nr,nc);
for row = 1:1:nr
for col = 1:1:nc
[~,loop_lat_ix] = min(abs(lat - row));
[~,loop_lon_ix] = min(abs(lon - -col));
loop_timeseries = squeeze(sst(loop_lat_ix,loop_lon_ix,:));
loop_seasonal_cycle = calc_seasonal_cycle(loop_timeseries,time);
cycle_range (row,col) = max(loop_seasonal_cycle(:))-min(loop_seasonal_cycle(:));
end
end
this gives me a matrix where the first 60 colomns in the first row give a value, and every other row and column is NaN.
2 commentaires
chrisw23
le 6 Déc 2022
How about to use a conditional breakpoint in your loop to debug the problem yourself?
Réponses (0)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!