drawing a point in the graph

Réponses (2)

Arif Hoq
Arif Hoq le 6 Déc 2022
Modifié(e) : Arif Hoq le 6 Déc 2022
x = 1:5;
y = 20:24;
plot(x,y,x(3),y(3),'*') % specify a marker symbol * in index 3 of y
please follow this for more information about plot

3 commentaires

thank you. How can I mark the point of intersection in the following case?
"
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g')
"
try this approach. I am not sure about his efficiency.
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
[x1equality ia]=find(ismember(t1,t2));
[x3equality ib]=find(ismember(t3,t4));
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g',x1(ia),t1(ia),'*',x3(ib),t3(ib),'*')
Ismita
Ismita le 7 Déc 2022
Thank you :)

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x = 0:0.5:10;
t = (x/2).^2;
abs(x-2*sqrt(t)) %cross-check weether x == 2*sqrt(t)
ans = 1×21
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
plot(x, t, '*-')

5 commentaires

Ismita
Ismita le 6 Déc 2022
Modifié(e) : Walter Roberson le 6 Déc 2022
thank you. How can I mark the point of intersection in the following case? TIA
t1 = 0:0.5:2;
x1 = t1/2-1;
t2 = 2:0.5:20;
x2 = t2 - sqrt(2*t2);
t3 = 0:0.5:1;
x3 = t3+1;
t4 = 1:0.5:11.6;
x4 = 2*sqrt(t4);
figure(1)
plot(x1, t1, 'b', x2, t2, 'r', x3, t3, 'k', x4, t4, 'g')
You need to calculate the point of interesection between (x2,t2) and (x4,t4) . Then you can plot() that point, specifying a marker. For example,
plot(interesection_x, intersection_y, 'b*')
Ismita
Ismita le 7 Déc 2022
Problem is, the point of intersection is only one point but the x and t limits are not from the same region (x1, x2, x3, x4 and corresponding t1, t2, t3, t4) plot. The intersection is x4==6.78233, t2==11.66
plot(x4==6.78233, t2==11.66,'r*') does not work
plot(6.78233, 11.66, 'r*')
It does not matter if there is no exact match for this in the curves, if it is the correct intersection point.
Unless, that is, what you want to do is find the closest point on each of the two curves and mark those close points rather than the intersection point?
Ismita
Ismita le 7 Déc 2022
thank you :)

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le 6 Déc 2022

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le 7 Déc 2022

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