Having this problem second time can anyone help?

a=[1.1];
b=[0.09];
x(1)=1.16; x(2)=1.32; x(3)=1.47; x(4)=1.65; x(5)=1.93;
for i=1:5
    y(i)=(log(x.^2-1))./log(a.*x.^2-b);
end

Unable to perform assignment because the indices on the left side are not compatible with the size of the right side.

y

Answer 1

[Arif Hoq]

a=1.1;
b=0.09;
% x(1)=1.16; 
% x(2)=1.32; 
% x(3)=1.47; 
% x(4)=1.65; 
% x(5)=1.93;
x=[1.16;1.32;1.47;1.65;1.93];
% y=(log(x.^2-1))./log(a.*x.^2-b)

for i=1:size(x,1)
    y(i)=(log(x(i).^2-1))./log(a.*x(i).^2-b);
end
y

y = 1×5

-3.2253 -0.4944 0.1804 0.5099 0.7221

%% without loop
a=1.1;
b=0.09;
x=[1.16;1.32;1.47;1.65;1.93];
y=log(x.^2-1)./log(a.*x.^2-b)

y = 5×1

-3.2253 -0.4944 0.1804 0.5099 0.7221