Automating the derivation of sensitivity indices

2 vues (au cours des 30 derniers jours)
Bas123
Bas123 le 22 Déc 2022
Commenté : Torsten le 30 Déc 2022
I am currently reviewing some papers on mathematical epidemiology and trying to replicate certain results on those papers. I want to calculate the sensitivity indices of model parameters (of the paper https://pubmed.ncbi.nlm.nih.gov/32834653/) with respect to the basic reproduction number using the formula where p is a parameter and is the sensitivity index of p. I have already calculated the indices manually, but I would like to know how to automate this process using MATLAB. The formula for and the parameter values are given below. The sensitivity index values given in the paper are . Thank you in advance!
beta_s = 0.274;
alpha_a = 0.4775;
alpha_u = 0.695;
mu = 0.062;
q_i = 0.078;
gamma_a = 0.29;
eta_i = 0.009;
eta_u = 0.05;
R0 = (beta_s*alpha_a)/(gamma_a+mu) + (beta_s*alpha_u*gamma_a*(1-q_i))/((gamma_a+mu)*(eta_u+mu))
  1 commentaire
Bas123
Bas123 le 29 Déc 2022
Does anyone have any ideas on this question? Thanks!

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Réponses (1)

Torsten
Torsten le 29 Déc 2022
Modifié(e) : Torsten le 29 Déc 2022
You could use
syms beta_s alpha_a alpha_u mu q_i gamma_a eta_i eta_u
beta_s_num = 0.274;
alpha_a_num = 0.4775;
alpha_u_num = 0.695;
mu_num = 0.062;
q_i_num = 0.078;
gamma_a_num = 0.29;
eta_i_num = 0.009;
eta_u_num = 0.05;
R0 = (beta_s*alpha_a)/(gamma_a+mu) + (beta_s*alpha_u*gamma_a*(1-q_i))/((gamma_a+mu)*(eta_u+mu));
%S_beta_s as an example
dR0dbeta_s = diff(R0,beta_s)
dR0dbeta_s = 
S_beta_s = beta_s_num/subs(R0,[beta_s alpha_a alpha_u mu q_i gamma_a eta_i eta_u],[beta_s_num alpha_a_num alpha_u_num mu_num q_i_num gamma_a_num eta_i_num eta_u_num])*subs(dR0dbeta_s,[beta_s alpha_a alpha_u mu q_i gamma_a eta_i eta_u],[beta_s_num alpha_a_num alpha_u_num mu_num q_i_num gamma_a_num eta_i_num eta_u_num])
S_beta_s = 
1
  6 commentaires
Bas123
Bas123 le 30 Déc 2022
Hey, thank you! Here is the Mathematica code that I used.
f[betas_, alphaa_, alphau_, mu_, qi_, gammaa_, etau_] := (betas*alphaa)/(gammaa+mu) + (betas*alphau*gammaa*(1-qi))/((gammaa+mu)*(etau+mu))
R0 = f[0.274, 0.4775, 0.695, 0.062, 0.078, 0.29, 0.05]
Sbetas = (betas/R0)*D[f[betas, alphaa, alphau, mu, qi, gammaa, etau], betas]
SbetasValue = Sbetas/.{betas->0.274, alphaa->0.4775, alphau->0.695, mu->0.062, qi->0.078, gammaa->0.29, etau->0.05}
Torsten
Torsten le 30 Déc 2022
I don't see a difference between MATLAB and MATHEMATICA code.
If the results are different, I'd compare intermediate results, e.g. R0 and dR0dbeta_s, in both programs.

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