The Y(:,81) changes linearly with respect to T, I want to modify my code in such a way that when Y(:,81) reaches 2.5E-6 then after that it remains constant through out with T.
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
ti = 0;
tf = 7E-12;
tspan=[ti tf];
k = 1E-6;
h = 1E-2;
y0= [(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
(h)*rand(2,1); ((-3.14).*rand(1,1) + (3.14).*rand(1,1));
((-3.14).*rand(20,1) + (3.14).*rand(20,1));
zeros(1,1);
];
yita_mn = [
0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1;
1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 1;
1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
];
N = 20;
tp = 1E-12;
o = sort(10e4*rand(1,20),'ascend');
[T,Y]= ode45(@(t,y) rate_eq(t,y,yita_mn,N,o,k),tspan./tp,y0);
r = ((1/20).*( exp(i.*Y(:,3)) + exp(i.*Y(:,6)) + exp(i.*Y(:,9)) + exp(i.*Y(:,12)) + exp(i.*Y(:,15)) ...
+exp(i.*Y(:,18)) +exp(i.*Y(:,21)) +exp(i.*Y(:,24)) + exp(i.*Y(:,27)) + exp(i.*Y(:,30)) + exp(i.*Y(:,33)) ...
+ exp(i.*Y(:,36)) + exp(i.*Y(:,39)) +exp(i.*Y(:,42)) + exp(i.*Y(:,45)) + exp(i.*Y(:,48)) + exp(i.*Y(:,51)) + exp(i.*Y(:,54))+ exp(i.*Y(:,57)) + exp(i.*Y(:,60))));
figure(1)
plot(T,Y(:,81),'linewidth',1.5)
xlabel("Time(in units of t_{p})")
ylabel("coupling")
grid on
set(gca,'fontname','times New Roman','fontsize',18,'linewidth',1.8);
%since it evolving linearly, how should I chnage the code so when it
%reaches 2E-6 it will become constant with respect to T
function dy = rate_eq(t,y,yita_mn,N,o,k)
dy = zeros(4*N+1,1);
dGdt = zeros(N,1);
dAdt = zeros(N,1);
dOdt = zeros(N,1);
P = 0.20;
a = 0;
T = 2000;
tp = 1E-12;
Gt = y(1:3:3*N-2);
At = y(2:3:3*N-1);
Ot = y(3:3:3*N-0);
for i = 1:N
dGdt(i) = (P - Gt(i) - (1 + 2.*Gt(i)).*((At(i)))^2)./T ;
dAdt(i) = Gt(i)*(At(i));
dOdt(i) = a.*Gt(i) + o(1,i).*tp;
for j = 1:N
dAdt(i) = dAdt(i) + (y(81)).*yita_mn(i,j)*(At(j))*cos(Ot(j)-Ot(i));
dOdt(i) = dOdt(i) + (y(81)).*yita_mn(i,j)*((At(j)/At(i)))*sin(Ot(j)-Ot(i));
end
end
dy(1:3:3*N-2) = dGdt;
dy(2:3:3*N-1) = dAdt;
dy(3:3:3*N-0) = dOdt;
n1 = (1:20)';
n2 = circshift(n1,-1);
n61 = n1 +60;
n62 = circshift(n61,-1);
n80 = circshift(n61,1);
j2 = 3*(1:20)-1;
j5 = circshift(j2,-1);
j8 = circshift(j2,-2);
j59 = circshift(j2,1);
dy(n61) = (o(1,n2).' - o(1,n1).').*tp + a.*(Gt(n2) - Gt(n1)) - (y(81)).*(y(j2)./y(j5)).*sin(y(n61)) - (y(81)).*(y( j5)./y(j2)).*sin(y(n61)) + (y(81)).*(y(j8)./y(j5)).*sin(y(n62)) + (y(81)).*(y(j59)./y(j2)).*sin(y(n80));
dy(81) = k;
end
0 commentaires
Réponses (1)
Les Beckham
le 3 Jan 2023
Over 100 lines of code to draw a straight line?
This plot (with the maximum Y limit applied) can be made in 8 lines of code:
T = [0 2.5 7];
Y = T*1e-6;
Y(Y>2.5e-6) = 2.5e-6; % apply the limit
plot(T,Y,'linewidth',1.5)
xlabel("Time(in units of t_{p})")
ylabel("coupling")
grid on
set(gca,'fontname','times New Roman','fontsize',18,'linewidth',1.8);
0 commentaires
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!