variable store in loop
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
syms z x a v
Y(1)=a
T=0
for k=1:2
Y(k+1)=z
v=0
for l=1:k
v=v+kroneckerDelta(sym(l-2))*(k+2-l)*(k+1-l)*Y(k+2-l) % THIS LINE
end
T= v+ 2*(k)*Y(k+1)+(kroneckerDelta(sym(l-2)))==0
a=solve(T,z)
Y(k+1)=a
end
The highlighted part is not getting updated. Why it is so? Y(2)=z is variable and this value is later used to calculate T.
0 commentaires
Réponses (1)
VBBV
le 4 Jan 2023
syms z x a v
Y(1)=a
T=0
for k=1:2
Y(k+1)=z;
v=0;
for l=1:k
v=v+kroneckerDelta(str2sym('l-2'))*(k+2-l)*(k+1-l)*Y(k+2-l);
end
T= v+ 2*(k)*Y(k+1)+(kroneckerDelta(str2sym('l-2')))==0
a=solve(T,z);
Y(k+1)=a;
end
6 commentaires
VBBV
le 5 Jan 2023
syms z x a v
Y(1)=a
T=0;
for k=1:2
Y(k+1)=z
v=0
for l=1:k
v=v+kroneckerDelta(sym(l-2))*(k+2-l)*(k+1-l)*Y(k+2-l) % THIS LINE
end
T= v+ 2*(k)*Y(k+1)+(kroneckerDelta(sym(l-2)))==0
a=solve(T,z)
Y(k)=a % may be this is change needed
end
Voir également
Catégories
En savoir plus sur Large Files and Big Data dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!