parse error at x0

4 vues (au cours des 30 derniers jours)
Janidu
Janidu le 4 Jan 2023
Commenté : Voss le 4 Jan 2023
Hello I'm new to matlab coding and here Im getting this parse error and I cannot figure it out. From this code I need to find the minimum of the function using steepest descent method. And I would like to know this code correct or not please.
this is my func : F (x,y) = 10x2−4xy+7y2−455x−y−16
and the starting point is : [ 0,10 ]
thanks for help!
%steepest descent method
function f = target_function(x, y)
f = 10 * x.^2 - 4 * x .* y + 7 * y.^2 - 20 * sqrt(5) * x + 4 * sqrt(5) * y - 16;
end
%parameters
x0 = [0 10];
eps = 0.01;
%initialization
point_min = x0';
target_func_min = target_function(point_min(1), point_min(2));
w = antigradient(point_min);
nw = norm(w);
tau = (1 + sqrt(5)) / 2;
%statistics
points(:, 1) = point_min;
target_func_values(1) = target_func_min;
iter_count = 0;
target_func_calls_count = 0;
%One-Dimensional Minimization Using the Golden Section Method
while nw > eps
iter_count = iter_count + 1;
kp = 0;
step = 0;
while abs(kp - step) < eps
a = step;
b = a + 2;
step = step + 2;
kp1 = ((b * (tau - 1) + a) / tau);
kp2 = ((a * (tau - 1) + b) / tau);
X = point_min + kp1 * w;
f_X1 = target_function(X(1), X(2));
X = point_min + kp2 * w;
f_X2 = target_function(X(1), X(2));
target_func_calls_count = target_func_calls_count + 2;
while norm(b - a) > eps
if (f_X1 > f_X2)
kp = kp2;
a = kp1;
kp1 = kp2;
kp2 = ((a * (tau - 1) + b) / tau);
f_X1 = f_X2;
X = point_min + kp2 * w;
f_X2 = target_function(X(1), X(2));
else
kp = kp1;
b = kp2;
kp2 = kp1;
kp1 = ((b * (tau - 1) + a) / tau);
f_X2 = f_X1;
X = point_min + kp1 * w;
f_X1 = target_function(X(1), X(2));
end
target_func_calls_count = target_func_calls_count + 1;
end
end
point_min = point_min + kp * w;
w = antigradient(point_min);
target_func_min = target_function(point_min(1), point_min(2));
nw = norm(w);
points(:, iter_count + 1) = point_min;
target_func_values(iter_count + 1) = target_func_min;
end
Min = min(min(points(1, :)), min(points(2, :)));
Max = max(max(points(1, :)), max(points(2, :)));
space = linspace(Min - 5, Max + 5, 500);
[gridX, gridY] = meshgrid(space, space);
gridJ = target_function(gridX, gridY);
figure;
contour(gridX, gridY, gridJ, target_func_values, 'black', 'ShowText', 'on');
hold on;
plot(points(1, :), points(2, :), 'r.-');
fprintf(func count: %.0f\n',target_func_calls_count);
fprintf(iter: %.0f\n\n', iter_count);
fprintf(min point: (%2.2f; %2.2f)\n', point_min);
fprintf(min value: %2.2f\', target_func_min);

Réponse acceptée

Voss
Voss le 4 Jan 2023
Looks like you are missing a single-quote at the beginning of each of your fprintf calls (and an "n" is missing in the last one):
fprintf(func count: %.0f\n',target_func_calls_count);
fprintf(iter: %.0f\n\n', iter_count);
fprintf(min point: (%2.2f; %2.2f)\n', point_min);
fprintf(min value: %2.2f\', target_func_min);
Should be:
fprintf('func count: %.0f\n',target_func_calls_count);
fprintf('iter: %.0f\n\n', iter_count);
fprintf('min point: (%2.2f; %2.2f)\n', point_min);
fprintf('min value: %2.2f\n', target_func_min);
  4 commentaires
Janidu
Janidu le 4 Jan 2023
I did that. But there are still errors. (
%steepest descent method
%parameters
x0 = [0 10];
eps = 0.01;
%initialization
point_min = x0';
target_func_min = target_function(point_min(1), point_min(2));
w = antigradient(point_min);
Unrecognized function or variable 'antigradient'.
nw = norm(w);
tau = (1 + sqrt(5)) / 2;
%statistics
points(:, 1) = point_min;
target_func_values(1) = target_func_min;
iter_count = 0;
target_func_calls_count = 0;
%One-Dimensional Minimization Using the Golden Section Method
while nw > eps
iter_count = iter_count + 1;
kp = 0;
step = 0;
while abs(kp - step) < eps
a = step;
b = a + 2;
step = step + 2;
kp1 = ((b * (tau - 1) + a) / tau);
kp2 = ((a * (tau - 1) + b) / tau);
X = point_min + kp1 * w;
f_X1 = target_function(X(1), X(2));
X = point_min + kp2 * w;
f_X2 = target_function(X(1), X(2));
target_func_calls_count = target_func_calls_count + 2;
while norm(b - a) > eps
if (f_X1 > f_X2)
kp = kp2;
a = kp1;
kp1 = kp2;
kp2 = ((a * (tau - 1) + b) / tau);
f_X1 = f_X2;
X = point_min + kp2 * w;
f_X2 = target_function(X(1), X(2));
else
kp = kp1;
b = kp2;
kp2 = kp1;
kp1 = ((b * (tau - 1) + a) / tau);
f_X2 = f_X1;
X = point_min + kp1 * w;
f_X1 = target_function(X(1), X(2));
end
target_func_calls_count = target_func_calls_count + 1;
end
end
point_min = point_min + kp * w;
w = antigradient(point_min);
target_func_min = target_function(point_min(1), point_min(2));
nw = norm(w);
points(:, iter_count + 1) = point_min;
target_func_values(iter_count + 1) = target_func_min;
end
Min = min(min(points(1, :)), min(points(2, :)));
Max = max(max(points(1, :)), max(points(2, :)));
space = linspace(Min - 5, Max + 5, 500);
[gridX, gridY] = meshgrid(space, space);
gridJ = target_function(gridX, gridY);
figure;
contour(gridX, gridY, gridJ, target_func_values, 'black', 'ShowText', 'on');
hold on;
plot(points(1, :), points(2, :), 'r.-');
fprintf('func count: %.0f\n',target_func_calls_count);
fprintf('iter: %.0f\n\n', iter_count);
fprintf('min point: (%2.2f; %2.2f)\n', point_min);
fprintf('min value: %2.2f\', target_func_min);
function f = target_function(x, y)
f = 10 * x.^2 - 4 * x .* y + 7 * y.^2 - 20 * sqrt(5) * x + 4 * sqrt(5) * y - 16;
end
Voss
Voss le 4 Jan 2023
I also got the error about "antigradient" being unrecognized. What is it?

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Contour Plots dans Help Center et File Exchange

Produits


Version

R2021b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by