cannot find existing number
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Luis Eduardo Cofré Lizama
le 8 Jan 2023
Commenté : Star Strider
le 8 Jan 2023
I have the following data where fs =100;
tstamp =(1/fs:1/fs:12000*(1/fs))
Then when looking for the value 117 (find(tstamp == 117)), the results is [], however, the value does exist though with a trail of zeros (117.0000), is that the prob? how to solve?
Please help with this very likely simple prob.
cheers
Eduardo
0 commentaires
Réponse acceptée
Star Strider
le 8 Jan 2023
Actually, I can’t reproduce that exact problem, since it works correctly here —
format long
fs =100;
tstamp =(1/fs:1/fs:12000*(1/fs))
v = find(tstamp == 117)
D = v - 11700
I was hoping to be able to demonstrate floating-point approximation error.
Oh well ...
.
3 commentaires
Walter Roberson
le 8 Jan 2023
There are various fairly obscure ways in which the floating point round-off algorithm can end up being changed. That does not happen often, but it can happen.
Plus de réponses (1)
Voir également
Catégories
En savoir plus sur Logical dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!