defining a fitting type

9 vues (au cours des 30 derniers jours)
Wout Laeremans
Wout Laeremans le 12 Jan 2023
Modifié(e) : Torsten le 16 Jan 2023
I have written a funcion called Even_fit.m and there are 5 coefficients that need to be found from the fit (a,b,c,d,f) and there is one variable N that I want to load from the workspace, which is already fixed before fitting. My question is how I can load this variable in the fit, since when I do:
ft_even = fittype("Even_fit(x,a,b,c,d,f,N)");
It will also take N as a fitting coefficient, which I do not want.
Thank you!

Réponse acceptée

Torsten
Torsten le 12 Jan 2023
Modifié(e) : Torsten le 12 Jan 2023
My guess is
fitType = @(x,a,b,c,d,f)Even_fit(x,a,b,c,d,f,N);
fit(x,y,fitType)
  2 commentaires
Wout Laeremans
Wout Laeremans le 16 Jan 2023
This does not work
Torsten
Torsten le 16 Jan 2023
Modifié(e) : Torsten le 16 Jan 2023
Put the vector of the independent variable to the end of the input list for your function "EvenFit":
x = linspace(0,1,10).';
y = 3*x.^2 + 0.1*rand(10,1);
n = 12;
fitType = @(a,b,c,x)Even_fit(x,a,b,c,n);
sol = fit(x,y,fitType)
Warning: Start point not provided, choosing random start point.
sol =
General model: sol(x) = Even_fit(x,a,b,c,n) Coefficients (with 95% confidence bounds): a = 2.803 (2.517, 3.09) b = 0.2072 (-0.09066, 0.505) c = 0.009327 (-0.05463, 0.07328)
plot(sol,x,y)
function yfit = Even_fit(x,a,b,c,n)
yfit = a*x.^2+b*x+c;
end

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Plus de réponses (1)

Steven Lord
Steven Lord le 12 Jan 2023
See the "Create Custom Nonlinear Models and Specify Problem Parameters and Independent Variables" and "Use Anonymous Functions to Work with Problem Parameters and Workspace Variables" examples on the fittype documentation page.

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