break out of for loop help
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have this for loop which works perfectly fine except that I want it to stop the for loop when y=0. The loop is calculating trajectory so I want it to stop when the ball hits the ground (or y=0). I have tried everything I can think of but nothing works. It either doesn't stop the loop or it returns the completely wrong y values. I've tried if y==0, y<=0, y(n)==0, y(n)<=0, y(n+1)==0, y(n+1)<=0, and putting it before and after the calculations. nothing worked Please help.
for n=1:N
ax(n+1) = -D*vx(n)*v(n);
ay(n+1) = -D*vy(n)*v(n)-g;
v(n+1) = sqrt(vx(n)^2+vy(n)^2);
x(n+1) = x(n)+T*vx(n)+0.5*T^2*ax(n);
vx(n+1) = vx(n)+T*ax(n);
y(n+1) = y(n)+T*vy(n)+0.5*T^2*ay(n);
vy(n+1) = vy(n)+T*ay(n);
if y(n+1)==0, break; end
end
2 commentaires
Réponse acceptée
Jan
le 21 Oct 2011
The loop does stop. You can check this by a disp statement before the break.
I assume you have written the code into a script and y is defiend from an earlier run. Then a "clear" statement on top would be helpful - not "clear all". Or you could convert it to a function by inserting this as first line:
function myIntegrator
or what ever your file is called.
Note: Using several commands in one line impedes debugging. You cannot set a breakpoint on the break command in:
if y(n+1)==0, break; end
But this would have revealed the problem.
Plus de réponses (1)
Image Analyst
le 20 Oct 2011
It probably won't hit 0.0000000000000000000 exactly. It might get to 0.000000000000002, so check if it's close:
if abs(y(n+1)) < 0.0001 % Some tolerance.
break;
end
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!