why MATLAB is busy for this code?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
1.What is the result?
creation=circshift(diag(sqrt(0:1:14)),-1);
annihilation=creation';
syms n
alpha = sym(0.03);
ketalpha1 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
syms n
alpha = sym(0.06);
ketalpha2 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
syms n
alpha = sym(0.09);
ketalpha3 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
syms n
alpha = sym(0.12);
ketalpha4 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
syms n
alpha = sym(0.15);
ketalpha5 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
syms n
alpha = sym(0.18);
ketalpha6 = symsum(exp(-abs(alpha)^2 * alpha^n / sqrt(factorial(n)) ), n, 0, 14);
V1=annihilation*ketalpha1-0.03*ketalpha1;
V2=annihilation*ketalpha2-0.06*ketalpha2;
V3=annihilation*ketalpha3-0.09*ketalpha3;
V4=annihilation*ketalpha4-0.12*ketalpha4;
V5=annihilation*ketalpha5-0.15*ketalpha5;
V6=annihilation*ketalpha5-0.18*ketalpha5;
Vnorm1=V1'*V1;
Vnorm2=V2'*V2;
Vnorm3=V3'*V3;
Vnorm4=V4'*V4;
Vnorm5=V5'*V5;
Vnorm6=V6'*V6;
alpha=[0.03;0.06;0.09;0.12;0.15;0.18];
Vnorm=[Vnorm1;Vnorm2;Vnorm3;Vnorm4;Vnorm5;Vnorm6];
size(alpha)
size(Vnorm)
plot(alpha,Vnorm)
xlabel('alpha','FontSize',12,'FontWeight','bold')
ylabel('Vnorm','FontSize',12,'FontWeight','bold')
2 commentaires
Torsten
le 15 Jan 2023
As you can see, alpha has dimension 6x1 and Vnorm has dimension 90x15.
How to plot Vnorm against alpha ?
Réponse acceptée
Walter Roberson
le 15 Jan 2023
My tests show it executing quickly but failing the plot.
annihilation is 15x15 so your Vnorm variables are 15x15. You [] 6 of those together to get 90 x 15 but expect to be able to plot that against 6 alpha values.
annihilation is created by a diag() so it is not going to be a vector.
0 commentaires
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Applications dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!