Next value in alphabet

I am trying to write a code to find a letter in the alphabet after the letter given, but I'm not sure which function specifies to choose the letter after. I've tried looking everywhere but I cant find it.

function [next] = nextLetter('char')

Alphabet = ('a';'b';'c';'d';'e';'f';'g';'h';'i';'j';'k';'l';'m';'n';'o';'p';'q';'r';'s';'t';'u';'v';'w';'x';'y';'z';)

next = find(ismember(Alphabet, ???)

Answer 1

[Les Beckham]

A simpler approach:

char('c' + 1)

ans = 'd'

Answer 2

[VBBV]

p = 'a'  % e.g. user enters input letter

p = 'a'

nextLetter(p)  % output of nextLetter 

ans = 1×1 cell array
    {'b'}

function [next] = nextLetter(p)
Alphabet = {'a';'b';'c';'d';'e';'f';'g';'h';'i';'j';'k';'l';'m';'n';'o';'p';'q';'r';'s';'t';'u';'v';'w';'x';'y';'z'};
next = find(ismember(Alphabet,p))+1;  % add +1 
next = Alphabet(next);
end

[VBBV]

Simply add +1 to the line , and pass the index to "Alphabet" array

next = find(ismember(Alphabet,p))+1;

Answer 3

[Voss]

nextLetter('d')

ans = 'e'

nextLetter('s')

ans = 't'

nextLetter('z') % no next letter after 'z' -> error

Index exceeds the number of array elements. Index must not exceed 26.

Error in solution>nextLetter (line 8)
next = Alphabet(idx);

function next = nextLetter(letter)
Alphabet = 'a':'z';
idx = find(Alphabet == letter)+1;
next = Alphabet(idx);
end

Answer 4

[Walter Roberson]

rot1('When is the time? The time for all good people, who come to the aid of their country!')

ans = 'Xifo jt uif ujnf? Uif ujnf gps bmm hppe qfpqmf, xip dpnf up uif bje pg uifjs dpvousz!'

function next = rot1(letter)
  Next(1:255) = char(1:255);
  Next('a':'y') = 'b':'z';
  Next('A':'Y') = 'B':'Z';
  Next('z') = 'a';
  Next('Z') = 'A';
  next = Next(letter);
end