Projection using Modified Gram-Schmidt orthogonality

Hello,
I need the Modified Gram-Schmidt orthogonalization method in my Research.
I wrote the following code for the projection using the Classic Gram-Schmidt:
function[Xp] = Project(A,B)
Xp = [] ;
u1 = B;
for i = 1:1:6
u2 = A(i,:)- (A(i,:)*u1)/(u1'*u1) * u1';
Xp = [Xp;u2] ;
end
end
I faced problems to convert the Modified Gram-Schmidt orthogonalization method into MATLAB code, which is illustrated in the following link https://en.wikipedia.org/wiki/Gram%E2%80%93Schmidt_process
under section Numerical stability.
Can anyone help me in this problem please?

22 commentaires

The question is what you want.
The two codes do very different things:
The first code orthonormalizes A, the second projects A on the subspace spanned by B.
M
M le 25 Jan 2023
@Torsten the second code uses the Classic Gram-Schmidt orthogonality to project A on B , my question is that I want to project A on B but using the Modified Gram-Schmidt.
I found the first code but i dont know how to apply it on the projection.
Thanks
Torsten
Torsten le 25 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
As said, projection is not normalization. To project a set of vectors A on a given vector B, you don't need Gram-Schmidt - neither classical nor modified.
You only need the projection formula
A_projected(i,:) = A(i,:)*B/(B.'*B) * B.';
M
M le 25 Jan 2023
@Torsten but I want it to be orthogonalized at the same time!!, Thats why I am using the Gram-Schmidt
M
M le 25 Jan 2023
@Torsten see in the following link :
"Methods for performing orthogonalization include:
I wrote this code based on the classical Gram-Schmidt
function[Xp] = Project(A,B)
Xp = [] ;
u1 = B;
for i = 1:1:6
u2 = A(i,:)- (A(i,:)*u1)/(u1'*u1) * u1';
Xp = [Xp;u2] ;
end
end
M
M le 25 Jan 2023
Modifié(e) : M le 25 Jan 2023
@Torsten but there are problems in statbility in the classical Gram-Schmidt , that's why I am looking to use the modified one.
Torsten
Torsten le 25 Jan 2023
Modifié(e) : Torsten le 25 Jan 2023
As said, projecting a set of vectors (rows of A) on one other vector (B) doesn't produce any problems.
Maybe the real problem you are trying to solve is different from what you do, but my abilities as clairvoyant are limited. So you should describe what you are trying to do. If it is really projecting a set of vectors on one given vector, you don't need Gram-Schmid - you only need the projection formula supplied. If you want to project a vector on the span of a set of vectors, the problem will be different.
M
M le 25 Jan 2023
Modifié(e) : M le 25 Jan 2023
@Torsten Ok, in my research there is a matrix that should be orthogonalized with a certain vector ( I want to use this info in the cost function). I searched on google about the vector orthogonalization technique and I found in the following link https://en.wikipedia.org/wiki/Orthogonalization
"Methods for performing orthogonalization include:
Gram–Schmidt process, which uses projection"
And now i am trying to apply this method, it uses projection to performe orthogonalization, I tried the classic method and it gives a resonable answers but as i said i want to try the modified one , but i need a help in it!!
Torsten
Torsten le 25 Jan 2023
Modifié(e) : Torsten le 25 Jan 2023
The statement "there is a matrix that should be orthogonalized with a certain vector" makes no sense to me. Could you elaborate ?
If it means that you want to extract the portion of each row of A that is orthogonal to this certain vector, then your function "Project" does the job. But since one vector is compared with only one other vector, there is no such thing as "modified Gram Schmid" for this application.
M
M le 25 Jan 2023
Modifié(e) : M le 25 Jan 2023
@Torsten In my problem there is a matrix A is always orthogonalized with vector B (this is the nature of the problem), I want to take advantage from this info and apply orthognalization methods as a cost function
M
M le 25 Jan 2023
Modifié(e) : M le 25 Jan 2023
@Torsten but if you check the section
Numerical stability
you will find something different from what you said!
Torsten
Torsten le 25 Jan 2023
Modifié(e) : Torsten le 25 Jan 2023
I already wrote that I don't understand what you mean by
In my problem there is a matrix A is always orthogonalized with vector B.
As a consequence, I also don't understand what you mean by
I want to take advantage from this info and apply orthognalization methods as a cost function
Maybe someone else in the forum gets it. Or you make an attempt to explain better.
M
M le 25 Jan 2023
@Torsten I just want to convert the section Numerical stability in the following link which illustrates the modified Gram-Schmidt : https://en.wikipedia.org/wiki/Gram%E2%80%93Schmidt_process
to matlab code in any example , because it faild with me.
This is all what I want, And then I will apply it to my variables.
You don't have a Gram-Schmid orthogonalization if you project several vectors separately on only one other vector. And this is what your "Project" function does. So there is no such thing as "Numerical Stability" you have to care about or that would change the projection formula.
If you want to project B on the row space of A, this would be a different thing.
But I repeat myself ...
@M Is there a reason you couldn't just use orth to orthogonalize A? Why must the orthogonalization be done with Modified Gram-Schmidt specifically?
M
M le 25 Jan 2023
Modifié(e) : M le 25 Jan 2023
@Torsten if I want to project B on the row space of A, what will be the different , in this case is there a need to use the Gram-Schmid method?. sorry but i am pretty new in this topic. Thanks
in this case is there a need to use the Gram-Schmid method?
Yes. The easiest way is to orthonormalize the row space first (maybe using modified Gram-Schmid) and then use the formula under
The easiest way is to orthonormalize the row space first (maybe using modified Gram-Schmid) and then use the formula under
Anything you didn't understand in my answer ? Or wasn't it what you were asking for ?
M
M le 26 Jan 2023
Hi @Torsten, Its not what I am looking for
Then I can assure you that from what you wrote, nobody will be able to understand what you are looking for.
Try to understand the problem first before looking for a solution.
@M: Please stop addressing specific users by messages like "Hi @xyz do you have any idea about my question please?"
Imagine what would happen, if all users do this: The most active users would receive a huge number of notifications and find less time to post answers.

Connectez-vous pour commenter.

 Réponse acceptée

Matt J
Matt J le 25 Jan 2023
Modifié(e) : Matt J le 26 Jan 2023
Aorth=orth(A); %A orthogonalized
ProjB=Aorth*(Aorth.'*B); %projection of B

38 commentaires

M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Matt J I didn't ask about general orthogonality, I need the Modified Gram-Schmidt orthogonalization in my research, and still I didn't solve the problem. Thanks
But you have been asked why you need Modified Gram-Schmidt specifically and haven't told us. What does it give you that orth() does not?
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Matt J Because I am working in an analytical problem and I need to discuss the difference of using several orthogonal techniques regarding my problem in the research but I have a problem in coding the Modified Gram-Schmidt and this is what i asked about in the question . Thanks
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Matt J I don't need such as a command. I need an algorithm.
but I have a problem in coding the Modified Gram-Schmidt and this is what i asked about in the question .
The modified Gram-Schmidt method was perfectly coded in the program you deleted from your question.
M
M le 26 Jan 2023
@Torsten, That program gives the Q and R decomposition , This is not what i need
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten I need the the projection algorithim of the Modified Gram-Schmidt , same as what I implemmented in the Classic Gram-Schmidt, Same as what illustrated in the section
Numerical stability
M
M le 26 Jan 2023
@Torsten I implemented a code for it but it didn't give good answers
Torsten
Torsten le 26 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
That program gives the Q and R decomposition , This is not what i need
Q contains the orthonormal basis from the modified Gram Schmidt procedure.
So don't delete codes that solve your problem.
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten how to use the Q to obtian the Projection of A on B ? and what the input X means?
I deleted it because i thought it is not the same. Thanks
This is the code that i have delete it
function [Q,R] = mgs(X)
% Modified Gram-Schmidt. [Q,R] = mgs(X);
% G. W. Stewart, "Matrix Algorithms, Volume 1", SIAM, 1998.
[n,p] = size(X);
Q = zeros(n,p);
R = zeros(p,p);
for k = 1:p
Q(:,k) = X(:,k);
for i = 1:k-1
R(i,k) = Q(:,i)'*Q(:,k);
Q(:,k) = Q(:,k) - R(i,k)*Q(:,i);
end
R(k,k) = norm(Q(:,k))';
Q(:,k) = Q(:,k)/R(k,k);
end
end
Matt J
Matt J le 26 Jan 2023
Modifié(e) : Matt J le 26 Jan 2023
how to use the Q to obtian the Projection of A on B ?
[Q,R]=mgs(B);
ProjA=Q*Q.'*A;
how to use the Q to obtian the Projection of A on B ?
ok, we go round in circles. The projection of vector A_j on B is
A_proj(j,:) = (A(j,:)*B)/(B.'*B) * B;
and a modified Gram-Schmidt method is not necessary to compute this projection.
Q contains the orthonormal basis from the modified Gram Schmidt procedure...So don't delete codes that solve your problem.
Except that it would probably be more efficient to just use Matlab's qr command if they give the same result,
A=rand(5,3);
Qmgs=mgs(A)
Qmgs = 5×3
0.0841 0.5572 -0.1058 0.5426 0.1513 -0.6618 0.7485 -0.2152 0.5957 0.0052 0.7840 0.3870 0.3718 0.0754 -0.2149
[Q,R]=qr(A,0);
Q=Q.*sign(diag(R)')
Q = 5×3
0.0841 0.5572 -0.1058 0.5426 0.1513 -0.6618 0.7485 -0.2152 0.5957 0.0052 0.7840 0.3870 0.3718 0.0754 -0.2149
function [Q,R] = mgs(X)
% Modified Gram-Schmidt. [Q,R] = mgs(X);
% G. W. Stewart, "Matrix Algorithms, Volume 1", SIAM, 1998.
[n,p] = size(X);
Q = zeros(n,p);
R = zeros(p,p);
for k = 1:p
Q(:,k) = X(:,k);
for i = 1:k-1
R(i,k) = Q(:,i)'*Q(:,k);
Q(:,k) = Q(:,k) - R(i,k)*Q(:,i);
end
R(k,k) = norm(Q(:,k))';
Q(:,k) = Q(:,k)/R(k,k);
end
end
M
M le 26 Jan 2023
@Torsten also I am repeating myself,my goal is to guarantee the orthogonality between A and B. Not THE PROJECTION itself! Gram Schmidt uses the projection as a tool to get the orthogonality .
For example House Householder transformation uses reflection to perform the orthogonalization and so on ....
Torsten
Torsten le 26 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
You partition A(j,:) in two parts: its projection on B ( (A(j,:)*B)/(B.'*B) * B ) and the part orthogonal to B: ( A(j,:) - (A(j,:)*B)/(B.'*B) * B ). Their sum gives A(j,:).
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten But I want to apply the modified Gram–Schmidt process !!
"Methods for performing orthogonalization include:
I need to study its efficiency to solve my problem. I dont need just final answer!
You need Gram-Schmidt if you want to compute a projection on a set of vectors.
So if you want to project B on A, you need Gram-Schmidt.
If you want to project A on B, you need one single line of code.
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten so good , I need this part "( A(j,:) - (A(j,:)*B)/(B.'*B) * B )." in my problem. This is what we call classic Gram–Schmidt process. but there is a simple modification in the modified Gram–Schmidt it should give the same answer of this part "( A(j,:) - (A(j,:)*B)/(B.'*B) * B )." .. But the coding of it faild with me.
M
M le 26 Jan 2023
@Torsten Ok , suppose i want to project B on A using the modified Gram–Schmidt , How can I code that?
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten " if you want to compute a projection on a set of vectors.
So if you want to project B on A, you need Gram-Schmidt. "
this is exactly what i am looking for using the modified Gram–Schmidt .
@M Then see above. The solution has already been presented.
M
M le 26 Jan 2023
[Q,R]=mgs(B);
ProjA=Q*Q.'*A;
This didnt give the same answer of the classic Gram–Schmidt "( A(j,:) - (A(j,:)*B)/(B.'*B) * B )."
M
M le 26 Jan 2023
it should be at least close @Matt J
Torsten
Torsten le 26 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
( A(j,:) - (A(j,:)*B)/(B.'*B) * B )." in my problem. This is what we call classic Gram–Schmidt process
This is what we call "projecting a set of vectors A onto a single vector B". There is no iterative process as in the Gram-Schmidt procedure involved. And since there is no Gram-Schmidt, there is no Modified Gram-Schmidt, either.
M
M le 26 Jan 2023
Modifié(e) : M le 26 Jan 2023
@Torsten suppose that A is the single vector and B is the set of vectors , Then we need the Modified Gram-Schmidt
Torsten
Torsten le 26 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
Now you want to change the roles of A and B ? Do you want to fool us ?
[Q,R]=mgs(B);
ProjA=Q*Q.'*A;
should give
(A(j,:)*B)/(B.'*B) * B
not
A(j,:) - (A(j,:)*B)/(B.'*B) * B
M
M le 26 Jan 2023
@Matt J , By subctracting the A from ProjA , We can get the orthogonal part , right?
M
M le 26 Jan 2023
@Torsten Nope, From the beginning I want any general code that do the orthogonalization by Modified Gram-Schmidt regardless my problem.
The projection of column vector A onto the column space of matrix B is the unique vector P satisfying B.'*(P-A)=0. The demo below shows that the procedure from above with Q produces this point and also agrees with the more usual least squares solution for the projection B*(B\A).
B=rand(5,3);
A=rand(5,1);
[Q,R]=qr(B,0);
Q=Q.*sign(diag(R)');
P1=Q*Q.'*A
P1 = 5×1
0.5921 0.7305 0.5290 0.2955 0.2067
P2=B*(B\A)
P2 = 5×1
0.5921 0.7305 0.5290 0.2955 0.2067
%Orthogonality test
B'*(A-P1)
ans = 3×1
1.0e-15 * -0.5829 -0.7772 -0.3331
A = rand(5,3);
B = rand(5,1);
[Q,R]=mgs(B);
ProjA=Q*Q.'*A
ProjA = 5×3
0.0893 0.2064 0.1511 0.0225 0.0520 0.0381 0.4198 0.9709 0.7106 0.1182 0.2734 0.2001 0.0302 0.0698 0.0511
for j = 1:3
(A(:,j).'*B)/(B.'*B) * B
end
ans = 5×1
0.0893 0.0225 0.4198 0.1182 0.0302
ans = 5×1
0.2064 0.0520 0.9709 0.2734 0.0698
ans = 5×1
0.1511 0.0381 0.7106 0.2001 0.0511
function [Q,R] = mgs(X)
% Modified Gram-Schmidt. [Q,R] = mgs(X);
% G. W. Stewart, "Matrix Algorithms, Volume 1", SIAM, 1998.
[n,p] = size(X);
Q = zeros(n,p);
R = zeros(p,p);
for k = 1:p
Q(:,k) = X(:,k);
for i = 1:k-1
R(i,k) = Q(:,i)'*Q(:,k);
Q(:,k) = Q(:,k) - R(i,k)*Q(:,i);
end
R(k,k) = norm(Q(:,k))';
Q(:,k) = Q(:,k)/R(k,k);
end
end
M
M le 26 Jan 2023
@Torsten Thanks. Now to get "A(j,:) - (A(j,:)*B)/(B.'*B) * B"
I have to do : A - ProjA , right?
Matt J
Matt J le 26 Jan 2023
Modifié(e) : Matt J le 26 Jan 2023
@M You must transpose A and B if you want to project rows instead of columns. Your code routine mgs() (and also matlab's qr() as we've seen) orthogonalizes the columns of the input X, not the rows.
Torsten
Torsten le 26 Jan 2023
Modifié(e) : Torsten le 26 Jan 2023
Yes, A - ProjA is the part of the columns of A orthogonal to B.
M
M le 26 Jan 2023
@Matt J Geart. Thank you very much
M
M le 26 Jan 2023
@Torsten very beneficial discussion. Thanks much.
I'm surprised you now found what you were searching for.
In the end, was it projecting a single vector onto a set of vectors or a set of vectors onto a single vector you were aiming at ?
M
M le 26 Jan 2023
@Torsten, my problem is an optimization problem. it contains equations and I need to know unknown values using several orthogonal techniques. Thanks

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Linear Algebra dans Centre d'aide et File Exchange

Question posée :

M
M
le 25 Jan 2023

Commenté :

Jan
le 28 Jan 2023

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by