Effacer les filtres
Effacer les filtres

Area under the Peak

4 vues (au cours des 30 derniers jours)
iqra kiran
iqra kiran le 5 Fév 2023
Hello,
I am using the following code to find the width, height and area of the peak,
load('data.csv')
X = data(:,1);
Y= data(:,2);
>> plot(X,Y)
findpeaks(Y,X,'MinPeakProminence',4,'Annotate','extents')
[pks,loc,w,p] =findpeaks(Y,X);
x = 1:length(data);
x_pks = x(loc);
area = trapz(x_pks, pks)
I am getting an error to find the area,as mentioned below
Array indices must be positive integers or logical values.
please suggest me the any solution.

Réponse acceptée

Sulaymon Eshkabilov
Sulaymon Eshkabilov le 5 Fév 2023
Here is the corrected code;
clearvars; clc
load('data.csv')
X = data(:,1);
Y = data(:,2);
plot(X,Y)
findpeaks(Y,X,'MinPeakProminence',4,'Annotate','extents')
[pks,Loc,width,psrom] =findpeaks(Y,X);
findpeaks(Y,X)
x = X;
% if there are more than 1 peak, then it is necessary to specify which one
x1=Loc(1)-width(1)/2;
x2=Loc(1)+width(1)/2;
area = trapz([x1,x2], [pks(1), pks(1)])
  2 commentaires
iqra kiran
iqra kiran le 6 Fév 2023
Thank you.
Sulaymon Eshkabilov
Sulaymon Eshkabilov le 6 Fév 2023
Most welcome

Connectez-vous pour commenter.

Plus de réponses (0)

Produits


Version

R2022b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by