How to do the following two for loop?

3 vues (au cours des 30 derniers jours)
M
M le 9 Fév 2023
Commenté : M le 10 Fév 2023
How to do the following two for loop?
i=0.1:0.1:0.9 ;
M=[1 1 1 1 1 1];
first outer loop :
In the 1st inner loop Assign i=0.9 on the first element, then in the 2nd inner loop Assign 0.8 on the first element till 0.1
then 2nd outer loop
In the 1st inner loop Assign i=0.9 on the 2nd element, in the 2nd inner loop Assign 0.8 on the 2nd element till 0.1
.
.
and so on .. till the 6th outer loop

Réponse acceptée

Torsten
Torsten le 9 Fév 2023
You mean
i=0.1:0.1:0.9 ;
M = [i.',ones(numel(i),5)]
M = 9×6
0.1000 1.0000 1.0000 1.0000 1.0000 1.0000 0.2000 1.0000 1.0000 1.0000 1.0000 1.0000 0.3000 1.0000 1.0000 1.0000 1.0000 1.0000 0.4000 1.0000 1.0000 1.0000 1.0000 1.0000 0.5000 1.0000 1.0000 1.0000 1.0000 1.0000 0.6000 1.0000 1.0000 1.0000 1.0000 1.0000 0.7000 1.0000 1.0000 1.0000 1.0000 1.0000 0.8000 1.0000 1.0000 1.0000 1.0000 1.0000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
?
  9 commentaires
Torsten
Torsten le 10 Fév 2023
Modifié(e) : Torsten le 10 Fév 2023
That's exactly what the code does (see above).
Or do you want the element of the outer loop remain at 0.1 instead of resetting it to 1 ?
Then delete the line
M(i) = 1.0;
M
M le 10 Fév 2023
@Torsten yes i deleted that line and now its working good. Thanks

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Plus de réponses (2)

Image Analyst
Image Analyst le 9 Fév 2023
Don't call variables "i" -- it's the imaginary constant.
Try this, for example to multiply M by 2
vec = 0.1:0.1:0.9
vec = 1×9
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000
M = [vec 1 1 1 1 1]
M = 1×14
0.1000 0.2000 0.3000 0.4000 0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.0000 1.0000 1.0000 1.0000
result = M * 2
result = 1×14
0.2000 0.4000 0.6000 0.8000 1.0000 1.2000 1.4000 1.6000 1.8000 2.0000 2.0000 2.0000 2.0000 2.0000
% Or via a for loop
for k = 1 : numel(vec)
result(k) = 2 * M(k);
end
To learn other fundamental concepts, invest 2 hours of your time here:

Image Analyst
Image Analyst le 10 Fév 2023
"assign i=0.9 on the first element, then assign 0.8 on the first element till 0.1"
Try this
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
result
result = 1×9
0.9000 0.8000 0.7000 0.6000 0.5000 0.4000 0.3000 0.2000 0.1000
  2 commentaires
M
M le 10 Fév 2023
I want to move into M=[i 1 1 1 1 1], it is an input for another function
Image Analyst
Image Analyst le 10 Fév 2023
OK, so did you do it? Again, don't use "i" as the name of your variable. That is something everyone here advises against.
for k = 1 : 9
result(k) = (10 - k) * 0.1;
end
M = [result, 1 1 1 1 1]

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