hwo to copy file

hey,

I am trying to copy multiple files (with different names) from one folder to another. however, filename is not accepting y as input because it is not an array, how to fix this?

Answer 1

[Sarvesh Kale]

Hi Yusra Malik,

If you are trying to copy all files inside trialfiles folder to folder named output then it is done as follows

source = fullfile('Users','macbook','Desktop','matlab','trialfiles');
destination = fullfile('Users','macbook','Desktop','matlab','ouptut');
copyfile(source,destination); % will copy all files from trialfiles folder to output folder

In your code filename should be set to a character vector of file name like 'trial.xlsx', basically fullfile constructs the filepath by receiving parts of file path as names and then adds the seperators '/' or '\' according to OS.

More information on fullfile and copyfile can be found in the following documentation

https://in.mathworks.com/help/matlab/ref/fullfile.html

https://in.mathworks.com/help/matlab/ref/copyfile.html

I hope this answers your queries, please accept the answer if it does

Thank you

Answer 2

[Venkat Siddarth]

Hi @Yusra Malik,

I understand that you are trying to copy a file from one directory to another using matlab.This can be achieved as follows:

Since you are trying to copy a file ,you have to provide the filename instead of loading the data and trying to save it.

clc
y = readtable('trial.xlsx');
p1 = '/Users/macbook/Desktop/matlab/trialfiles';
pdest = '/Users/macbook/Desktop/matlab/output';
filename = 'trail.xlsx' %%% filename variable should have filename instead of data loaded from file.
source = fullfile(p1,filename);
destination = fullfile(pdest,filename);
copyfile(source,destination);

I hope this resolves your query.

Thanks,

Venkat Siddarth V

[Yusra Malik]

this give me an error that not matching file name trial.xlsx

when i used the actual file name in filename = ' ' then it works fine.

my goal is to get the filename from excel sheet called trial.xlsx rather than having to input file name again and again.

[Venkat Siddarth]

Since the vector of filename is not supported in the fullfile function you can try the below iterative approach

%assuming that all the filenames are in first column of the excel sheet.
clc
y = readtable('trial.xlsx');
p1 = '/Users/macbook/Desktop/matlab/trialfiles';
pdest = '/Users/macbook/Desktop/matlab/output';
data=y{:,1};
%Iterating over each file name.
for i=data
filename = i 
source = fullfile(p1,filename);
destination = fullfile(pdest,filename);
copyfile(source,destination);
end

%Hope this resolves the issue

Answer 3

[Sulaymon Eshkabilov]

There are a couple of points which were not consistent. Here is the corrected code.

clc

SourceF = 'trial.csv';
y = readtable(SourceF);
p1 = 'C:\Users\17018\Documents\MATLAB';
pdest = 'C:\Users\17018\Documents';

filename = 'trial_COPY.csv';
source = fullfile(p1,SourceF);
destination = fullfile(pdest,filename);
copyfile(source,destination);

[Yusra Malik]

my goal is to get the filename from excel sheet called trial.xlsx rather than having to input file name again and again. if i write the filename = 'name' manually it works fine and copies but when i try to loop it cell by cell it gives an error "arguement must b scalor'.

the following works perfectly.

% y = readtable('trial.xlsx');

% p1 = '/Users/macbook/Desktop/matlab/trialfiles';

% pdest = '/Users/macbook/Desktop/matlab/output';

% filename = 'a4cf670f-1627-42cf-9917 fc2c89708353.rna_seq.augmented_star_gene_counts.csv'

% source = fullfile(p1,filename);

% destination = fullfile(pdest,filename);

% copyfile(source,destination);

Answer 4

[Image Analyst]

See attached demo.