Transfer Function from Linearization is not correct. Simscape Model.
Afficher commentaires plus anciens
Hello,
I am modeling a double pendulum on Simscape. This is a system of two masses that are hanging on flexible beams which models a kind of spring.
.

Here is what I do:
- I run the simulation to reach the steady state.
- I Linearize (from control system toolbox) my system around the steady state and I look at the 6 degrees of freedom of the bottom mass as output and the 6 degrees of freedom of the ground as input.
% Ground Input (1:6)
io(io_i) = linio([mdl, '/Ground_x'], 1, 'openinput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/Ground_y'], 1, 'openinput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/Ground_z'], 1, 'openinput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/Ground_xr'],1, 'openinput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/Ground_yr'], 1, 'openinput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/Ground_zr'], 1, 'openinput'); io_i = io_i + 1;
% IPP Center Output (37:42)
io(io_i) = linio([mdl, '/IPPx'], 1, 'openoutput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/IPPy'], 1, 'openoutput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/IPPz'], 1, 'openoutput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/IPPxr'],1, 'openoutput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/IPPyr'], 1, 'openoutput'); io_i = io_i + 1;
io(io_i) = linio([mdl, '/IPPzr'], 1, 'openoutput'); io_i = io_i + 1;
G = linearize(mdl,io,50);
- I take a transfer functions from the linearization.
With a siplified version of this model, (no flexible beams but prismatic joints instead), This is the transfer function that I manage to have:

There is all the modes that I expect.
On this version, all the Bases and Followers of the joints are matching at the linearization operating point.
Then, on this new version, the physics of the simulation works well, but the transfer function is completly incorrect:

But it should be very similar.
The only difference that I have found is that the Bases and followers of the top gimbal joints are not matching at the operating point because of the flexure of the beam.

The thing is that I don't understand the real reason why this is not working. Is that from Linearize or from Simscape?
Thank you for your help,
Vermeer
12 commentaires
Vermeer Bonhomme
le 13 Fév 2023
Shouldn't that be ss(output,input)?
I thought the simplified model was without flexible beams and the new version model is with flexible beams. Is that not the case?
The flexible beams are non-linear elements? How so?
From the question, I thought there were only two models in question, w/ and w/o flexible beams. Is there also a third model that showed this same concerning behavior between those two models.
Why is the linearization being taken as a snapshot at t = 50, as opposed to, say, t = 40 or t = 30? Is the system being stimulated by an external input and it takes 50 seconds to reach steady state?
Vermeer Bonhomme
le 13 Fév 2023
Paul
le 14 Fév 2023
It might be profitable to understand the changes and their effect in the second bullet.
Based on your physical understanding of the system, how many degrees-of-freedom does it have? How many states are in the output G of the linearize command?
Does SimScape allow you to define constraints at the configuration, velocity, or acceleration levels? If so, do you have any of those?
Vermeer Bonhomme
le 14 Fév 2023
Vermeer Bonhomme
le 14 Fév 2023
Paul
le 14 Fév 2023
No need to share the models, at least not for me.
If the system has 60 degrees of freedom, then for an unconstrained configuration
size(G.A,1)
should return 120. Is that the case?
Vermeer Bonhomme
le 15 Fév 2023
Paul
le 16 Fév 2023
Have you tried running the simulation from an initial condition with no forcing input, collecting the time-domain outputs, and then doing a quick FFT anlaysis of those outputs to see if the modal frequencies are consistent with your expectations or with the output of linearize?
Vermeer Bonhomme
le 3 Mar 2023
Paul
le 3 Mar 2023
Excellent. I completely forgot that the solver can influence the linearization in some cases. With a DAE solver, as I assume that daessc is, I imagine that can be even trickier.
Réponse acceptée
Plus de réponses (0)
Catégories
En savoir plus sur Trimming and Linearization dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!