How to find the order of the power of A matrix?

Hi, I want to calculate the order of the power matrix A. Here order doesn't mean for rows into columns but the power n of the matrix in modulo 2.

For example:

I try to wrote the code, but not getting the desired reults i.e., 3. Here's the code:

A = [1 0 1;1 1 0;1 0 0];
B = A;
i = 0;
for n = 1:5
    P = A*B;
    if P == eye(3)
        i = i+1;
        break;
    else
        if mod(P(:,:),2)==0
            B(mod(P(:,:),2)==0) = 0
        else
            B(mod(P(:,:),2)~=0) = 1
        end
        P = A*B;
    end
     i = i+1;
end

B = 3×3

1 0 1 1 1 1 1 0 1

B = 3×3

1 0 1 1 1 1 1 0 1

B = 3×3

1 0 1 1 1 1 1 0 1

B = 3×3

1 0 1 1 1 1 1 0 1

B = 3×3

1 0 1 1 1 1 1 0 1

disp(i)

     5

Please help me out.

Thanks

Answer 1

[Dyuman Joshi]

Use isequal to compare matrices and you can directly calculate modulo by mod, you don't need to assign the values specifically -

A = [1 0 1;1 1 0;1 0 0];
B = A;
i = 0;
for n = 1:5
    if isequal(B, eye(3))
        i = i+1;
        break;
    else
        sprintf('multiplication')
        B = A*B
        sprintf('calculating modulo 2')
        B = mod(B,2)
    end
    i = i+1;
end

ans = 'multiplication'

B = 3×3

2 0 1 2 1 1 1 0 1

ans = 'calculating mod'

B = 3×3

0 0 1 0 1 1 1 0 1

ans = 'multiplication'

B = 3×3

1 0 2 0 1 2 0 0 1

ans = 'calculating mod'

B = 3×3

1 0 0 0 1 0 0 0 1

disp(i)

     3

[Muhammad Usman]

I also need to this condition

B(mod(P(:,:),2)~=0) = 1

that when mod of 2 not equal to zero, replace the entry by 1

[Dyuman Joshi]

mod of 2 can only have 2 values, if mod of 2 is not equal to 0 then it is equal to 1.

I have edited my answer, so you can take a look at each step for every iteration.

Answer 2

[Stephen23]

A = [1,0,1;1,1,0;1,0,0];
B = A;
for n = 2:5
    B = mod(B*A,2);
    if isequal(B,eye(3))
        break
    end
end
n

n = 3

B

B = 3×3

1 0 0 0 1 0 0 0 1