关于polyeig函数为什么polyeig(A,0,B)与polyeig(A,B)输出的结果不一样
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why polyeig(A,0,B) not euqal to polyeig(A,B)
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Abhijeet
le 9 Mar 2023
Hi 定毅,
The command polyeig(A, 0, B) computes the eigenvalues of the matrix polynomial A - lambda*B evaluated at lambda=0. This is equivalent to computing the eigenvalues of the matrix A multiplied by the inverse of B.
The command polyeig(A, B) computes the eigenvalues of the matrix polynomial A - lambda*B.
The reason is that evaluating the matrix polynomial at different values of lambda can lead to very different results.
Thanks
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