How to combine two vectors column-by-column?

I have two matrices, A and B.

A = [1,3,5,7,9,11,13,15]

A = 1×8

1 3 5 7 9 11 13 15

B = [2,4,6,8,10,12,14,16]

B = 1×8

2 4 6 8 10 12 14 16

How can I combine these two to give me a third matrix C, which is as follows?

C = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]

C = 1×16

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

So, basically, C should be [A(:,1), B(:,1), A(:,2), B(:,2), ...]

Answer 1

[Stephen23]

A = [1,3,5,7;9,11,13,15;17,19,21,23]

A = 3×4

1 3 5 7 9 11 13 15 17 19 21 23

B = [2,4,6,8;10,12,14,16;18,20,22,24]

B = 3×4

2 4 6 8 10 12 14 16 18 20 22 24

C = reshape(permute(cat(3,A,B),[1,3,2]),size(A,1),[])

C = 3×8

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

[Stephen23]

A = [1,3,5,7;9,11,13,15;17,19,21,23];
B = [2,4,6,8;10,12,14,16;18,20,22,24];

Another approach:

C = repelem(A,1,2);
C(:,2:2:end) = B

C = 3×8

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24

Answer 2

[Sarvesh Kale]

Hi Jake,

You can see the following code snippet

A = [1,3,5,7,9,11,13,15];
B = [2,4,6,8,10,12,14,16];
C=[A;B] % row wise concatenation 

C = 2×8

1 3 5 7 9 11 13 15 2 4 6 8 10 12 14 16

C=C(:)';  % traversal will be column wise as matrix elements are stored in column major format 
C 

C = 1×16

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16

I hope this helps your query

Thank you

[Jake]

Thank you for the solution, @Sarvesh Kale! I'm curious to know how could one do this when the matrices are multi-dimensional. For instance, what if,

A = [1,3,5,7;9,11,13,15;17,19,21,23]

A = 3×4

1 3 5 7 9 11 13 15 17 19 21 23

B = [2,4,6,8;10,12,14,16;18,20,22,24]

B = 3×4

2 4 6 8 10 12 14 16 18 20 22 24

How could we get the matrix C by combining every-other column of A, and B, such that, (simply to demonstrate)?

C = [1,2,3,4,5,6,7,8; 9,10,11,12,13,14,15,16; 17,18,19,20,21,22,23,24]

C = 3×8

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24